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KATRIN_1 [288]
3 years ago
10

Eli has saved $48.50. Eli's brother borrowed 1/10 of Eli's savings. How much money does Eli have left?

Mathematics
2 answers:
Akimi4 [234]3 years ago
6 0

Answer:

Mark me as Brainlieist

Step-by-step explanation:

\frac{1}{10} of $48.50

=$4.85

Answer=48.5-4.85

<h2>=$43.65</h2>

zimovet [89]3 years ago
5 0

Answer:

$43.65

Step-by-step explanation:

1. divide 48.50 by 10

4.85

2. subtract 4.85 from 48.50

3. your answer would be $43.65

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Your professor assigns five short­-answer questions and then randomly selects one for a quiz. what is the probability that she w
MaRussiya [10]

Hello!

Since there are five short-answer questions and she randomly selects one for a quiz, this can be written as 1/5 because there are 5 choices, but only one can be selected.

Therefore, the probability that she will select question #3 is a 1/5 or 0.2 chance.

7 0
3 years ago
A sample of bacteria is growing at a rate of 8% per hour compound continuously. How many hours will it take for the sample to do
Anettt [7]

Answer:

The sample would double in 9 hours

Step-by-step explanation

The number of hours it will take for the sample to double can be found using the 72 rule.

The 72 rule is such that a growth rate would double itself by it is used in dividing the number 72 as shown below:

number of hours =72/8=9 hours

The number of hours it would take the sample to double is 9 hours as computed above.

6 0
3 years ago
David is filling out orders for an online business and gets paid $1 for each order he fills out plus bonus of 25 cents per order
svp [43]

Answer:

David will make $481 (he earns the bonus)

Explanation:

<em>If he makes $1 for each order and he filled out 385 orders, then why can't we say he made $385?</em>

Because of this statement rights here:

"...and gets paid $1 for each order he fills out plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20."

So we need to find out if any of the 3 weeks has an average of 20+ orders per day.

<h2>David is filling out orders for an online business and gets paid $1 for each order he fills out</h2>

(x is the amount of orders he fills out)

profit = $1x

<h2>plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20. </h2>

if any average orders per day is > 20 in any week

bonus profit = $1.25x

<h2>The ratio of the number of orders he processed during the first week to the number of orders he processed during the second week is 3:2, </h2>

first week     second week

             3a : 2a

<h2>while the the ratio that compares the number of orders he filled out during the first and the third weeks is 4 to 5 respectively. </h2>

first week   third week

           4a : 5a

<h2>What amount of money will David make at the end of three weeks if the total number of orders he filled out was 385?</h2>

sum of all ratios of a = 385

So we have

3a : <u>2a</u> (first week to <u>second week</u>)

4a : <em>5a </em>(first week to <em>third week</em>)

Notice how the first two numbers are both from the first week. Let's use the Least Common Multiple to make them equal while still keeping ratios.

LCM of 3 and 4: 12 = 3 * 4

12a : <u>8a</u> ( times 4 )

12a : <em>15a</em> ( times 3 )

Now that we have the same value, we can create a big ratio

first week <u>second week</u> <em>third week</em>

   12a     :        <u>8a</u>          :      <em>15a</em>

we know that these ratios will all equal 385. Since ratios are equal no matter how big we make them, we can say that

12a + <u>8</u>a + <em>15</em>a = 385 (a is a variable to scale up the ratio)

which is the same as

(12 + <u>8</u> + <em>15</em>) * a = 385

(<em><u>35</u></em>) * a = 385

35a = 385

if we solve for a by dividing 35 on both sides we get

a = 11

This gives us how much to multiply the RATIO by to get the ACTUAL NUMBER of orders completed. Let's plug 11 for 'a' and see what happens.

12a + <u>8</u>a + <em>15</em>a = 385

12(11) + <u>8</u>(11) + <em>15</em>(11) = 385

132 + <u>88</u> + <em>165</em> = 385     (Check that out, the number of orders each week!)

<u>220</u> + <em>165</em> = 385

<em><u>385</u></em> = 385

Bingo! All the math works out. So, looking back at the verryyy top of this problem, the reason why it wasn't as easy as $385 was because of the bonus.

The bonus gives David $1.25 per order instead of $1 per order if any of the weeks have an average ORDER PER DAY of anything bigger than 20. If we know the real numbers of orders for every week (132, <u>88</u>, and <em>165</em>), then we can divide it by 7 to get the average order per day. Let's choose <em>165 </em>(the <em>third week</em>) because it is the biggest and has the greatest chance of meeting our goal.

165 orders / 7 days (7 days in a week) = 23.57 orders per day

Is this greater than 20 orders per day?

YES!

So now we can safely say that the bonus is there or not, and in this case, the bonus IS there because there is a week where David had more than 20 orders per day.

So instead of using

profit = $1x

We will use

bonus profit = $1.25x

(x is the amount of orders completed)

So if we know he completed 385 orders, and we know he earned the bonus, we plug in 385 for x for the bonus function

bonus profit = $1.25x

bonus profit = $1.25 * 385

bonus profit = $481.25

If necessary, round your answer to the nearest dollar.

So for the very end, all we have to do is round it to the nearest dollar.

$481.25 rounds to $481.

And we're done!

8 0
3 years ago
20pts<br> how do you solve 3x-2y=14?
Furkat [3]
X(3) - Y(2) = 14. So you need numbers that will multiply by 3 and a number that multiply by 2 that will equal 14.
The x can be 10 (equals 30) and then y can be 8 (equals 16).
30 subtracted by 16 equals 14.

ANSWER:


X = 10 Y = 16
3(10) - 2(8) = 14

Hope this helped. Have a great day. A thank you and (or) brainliest is always appreciated. Goodbye!
4 0
3 years ago
You work 3:30pm-9:00pm. you take a break from 6:00 to 6:30. How many hours do you work in a day
lina2011 [118]

Answer:

You would work 5 hours a day

6 0
3 years ago
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