Question

What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?

Answer 1

The value of 'k' in the quadratic Equation    $4x^{2}+kx+4=0$ having one rational solution is k is 8.

What is a Quadratic Equation?

• Quadratic equations are the polynomial equations of degree 2 in one variable of the type $f(x) = ax^{2} + bx + c = 0$ where a, b, c, ∈ R and a ≠ 0.
• The standard form of a quadratic equation is $ax^{2} + bx + c = 0$ .

Here, the given equation is  $4x^{2}+kx+4=0$

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means $b^{2} -4ac=0$

Therefore,

$k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8$

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

#SPJ4