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nirvana33 [79]
2 years ago
14

What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0

The value of 'k' in the quadratic Equation    4x^{2}+kx+4=0 having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>
  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is  4x^{2}+kx+4=0

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means b^{2} -4ac=0

Therefore,

k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

#SPJ4

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