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3 years ago

Find the volume of a cylinder that has a diameter of 12 in. and a height of 15 in

Mathematics

2 answers:

daser333 [38]3 years ago

6 0

Answer:

<h3> $\sf{ \boxed{ \bold{1697.14}}}$ </h3>

Step-by-step explanation:

Given,

diameter ( d ) = 12 in

height ( h ) = 15 in

finding the radius of a cylinder

Radius is just half of diameter.

Radius ( r ) = 12 / 2 = 6 in

finding the volume of a cylinder having radius of 6 in and height of 15 in

Volume of a cylinder =  $\sf{\pi \: {r}^{2} h}$ 

⇒ $\sf{ \frac{22}{7} \times {6}^{2} \times 15}$

⇒ $\sf{ \frac{22}{7} \times 36 \times 15}$

⇒ $\sf{1697.14} \: in$ 

Hope I helped!

Best regards!!

charle [14.2K]3 years ago

3 0

Answer: 1697.1 $in^{3}$

Step-by-step explanation:

diameter= 12

radius= $\frac{diameter}{2}$ = $\frac{12}{2}$ = 6

height = 15

volume =π $r^{2}$ h

$\frac{22}{7} X 6^{2} X 15$ =1697.1 $in^{3}$

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Which describes the calculations that could be used to solve this problem? Lauren has 42 muffins to pack into boxes and bags. Sh

Marat540 [252]

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3 years ago

Read 2 more answers

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

e) $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

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3 years ago

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sammy [17]

Answer:

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Step-by-step explanation:

Assume that the width of the carpet is x inches

∵ The width of the carpet is x inches

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∴ The length of the carpet is (x + 67) inches

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→ Equate the two right sides of the perimeter

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→ Add the like terms in the left side

∴ (x + x) + 67 = 97

∴ 2x + 67 = 97

→ Subtract 67 from both sides

∵ 2x + 67 - 67 = 97 - 67

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→ Divide both sides by 2

∴ x = 15

∵ x represents the width of the carpet

∴ The width of the carpet is 15 inches

∵ The length of the carpet = 15 + 67

∴ The length of the carpet is 82 inches

∴ The dimensions of the carpet are 15 inches and 82 inches

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