Question

Two individuals who are heterozygous for Huntington’s are pregnant with a child. What is the probability that the resulting child will not inherit Huntington’s disease ?
Calculate the probability. The Punnett square is provided to show your work

Answer 1

The probability that the child will not inherit Huntington’s disease is therefore 1/4.

What is Probability?

This is defined as a numerical description of how an event is likely to occur and the formula is :

Number of favourable outcomes/Total Number of outcomes.

When the heterozygous traits(Hh × Hh) are crossed, we have HH, Hh, Hh, hh.

The recessive trait is hh which makes the probability to be 1/4 in which the resulting child will not inherit the disease.

Read more about Probability here brainly.com/question/13604758

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