CosA=(21^2+23^2-25^2)/2*21*23
cosA=345/966
A=cos^-1(345/966)
A=69.08
cosA=345/966
A=cos^-1(345/966)
A=69.08
The length of a rectangle is 3 inches more than its width, and its perimeter is 22 inches. Find the width of the rectangle.
1 answer:
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Answer:
Step-by-step explanation:
In the diagram shown, the measure of angle 1 is oppositely directed to angle 2 and oppositely directed angles are equal.
Hence <1 = <3
Given < 1 = 3x-1 and <3 = 2x+9
Hence 3x-1 = 2x+9
collect like terms
3x-2x = 9+1
x = 10°
Since <1 = 3x-1
on substituting x = 10
<1 = 3(10)-1
<1 = 30-1
<1 = 29°
<1+<2 = 180 (angle on a straight line)
29+<2 = 180
<2 = 180-29
<2 = 151°
Similarly, on substituting x = 10 into <3
<3 = 2x+9
<3 = 2(10)+9
<3 = 20+9
<3 = 29°
<3+<4 = 180 (angle on a straight line)
29+<4 = 180
<4 = 180-29
<4 = 151°
To solve this problem, we have to use the area of both gauze or the dimensions on each gauze and compare them. we can see that the sheets are not similar as they have different areas.
<h3>Area of Rectangle</h3>The area of a rectangle is given as the product between the length and it's width.
Data;
- Length = 9in
- Area = 45in^2
- width = ?
- length 2 = 4in
- width 2 = 3in
In the first gauze, the area is given as 45in^2 and we have value of the length. To find the width of the first gauze can be calculated as
We can see that the width are not equal so is their length.
But if we would truly compare them, the accurate way to do that is by their area
The area of the second gauze is given by
From the above calculations, we can see that the sheets are not similar as they have different areas.
Learn more on area of a rectangle here;