A game involves spinning this spinner. What is the probability of the pointer landing on Y ?

1 answer:

6 0

Here are the steps to answer this question:

1. Find the denominator. Since there is 8 possible outcomes, our denominator will be 8.

2. Find the numerator. To do this we need to find out of all the 8 possible outcomes, how many are them are y. Since its only 1 y, the numerator will be 1.

3. Now all we have to do now is make our fraction. The 8 possible outcomes given, only one of them has y which means that our fraction will be 1/8.

4. Answer: 1/8 or .125 or 12.5% chance for the spinner to land on y. I hope this helps!

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GREYUIT [131]

Answer:

$32.5

Step-by-step explanation:

(0.30*6)*3 + (0.30*8)*5 + 0.30*9 + (0.30*10)*7 + (0.30*12)*4 + (0.30*13)*2 + 0.30*14 = 67.5

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The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.

pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

$m_{1}\times m_{2}=-1$

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

$m_{normal} \times m_{tangent}=-1$

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

$m=\frac{y_2-y_1}{x_2-x_1}$