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lisov135 [29]
2 years ago
6

2. State two (2) values of θ (theta) to the nearest degree for sin θ = − 0. 966

Mathematics
1 answer:
emmasim [6.3K]2 years ago
5 0

Using equivalent angles, the solutions to the equation are given as follows:

\theta = 255^\circ, \theta = 285^\circ

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the equation is:

\sin{\theta} = -0.966

Applying the inverse relation:

\theta = \arcsin{-0.966} = 255^\circ

Which is on the third quadrant. The equivalent angle on the fourth quadrant is given as follows:

270^\circ + (270^\circ - 255^\circ) = 285^\circ

More can be learned about equivalent angles at brainly.com/question/28025397

#SPJ1

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When csc(O)sin(0) is simplified, what is the result?
Olin [163]

Answer:

This is not my answer, it was done by another expert in Brainly.

We are given:  

csc (0) * sin (0)  

This is to be simplified using trigonometric identities:  

csc (x) = 1/sin(x)  

so, csc (0) = 1/sin(0)  

then,  

1/sin(0) * sin (0), the result will be sin(0) / sin (0) which is equal to 1.  

Therefore, the answer is 1.

3 0
3 years ago
1/7 x X =1 <br> X x 1/11=1<br> 1 divided by 1/5=
guajiro [1.7K]

Answer:

  1. x = 7
  2. x = 11
  3. 5

Step-by-step explanation:

\frac{1}{7}  \times x = 1

7 \times  \frac{1}{7} x = 7 \times 1

7 \times  \frac{1}{7} x = 7

\boxed{\green{x = 7}}

◇◇•◇◇

x \times  \frac{1}{11}  = 1

\frac{1}{11} x  = 1

11 \times  \frac{1}{11} x = 11 \times 1

11 \times  \frac{1}{11} x = 11

\boxed{\green{x = 11}}

♤♤•♤♤

1 \div  \frac{1}{5}  = 1 \times  \frac{5}{1}

1 \times 5

\boxed{\green{= 5}}

4 0
3 years ago
B. (3.9) and (4.6)<br> The rate of change between these two points is
USPshnik [31]

Answer: 0.7 is the rate change between the two points

3 0
3 years ago
José sale de su casa con $50 y gasta 4/5 en el cine y 1/10 en chocolates, ¿qué fracción del
netineya [11]

Answer:

9/10

Step-by-step explanation:

8 0
3 years ago
Find the rate of change of the function h(x) = 2 x on the interval 2 ≤ x ≤ 4
dangina [55]
For a linear function, the instantaneous rate of change is everywhere equal to the slope. Thus the rate of change of the function h(x)=2x on the interval 2≤x≤4
The rate of change of the function given will equal to its slope, thus;
slope,m=(y-1-y)/(x_1-x)
=(2*4-2*2)/(4-2)
=(8-4)/2
=4/2
=2

the answer is 2 
7 0
3 years ago
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