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xeze [42]
1 year ago
5

Two identical firms compete as a Cournot duopoly. The inverse market demand they face is P = 123 - 3Q. The total cost function f

or each firm is TC(Q) = 3Q. The price charged in this market will be
Business
1 answer:
Varvara68 [4.7K]1 year ago
5 0

The price changed in this market will be mathematically given as

P=93

<h3>What is the price change in this market?</h3>

P = 123 - 3Q

Generally, the equation for the statement is  mathematically given as

P = 123 - 3Q

Therefore

\frac{d \pi}{ d \Q1}=123-6Q1-30Q2-3=0

Where

Q1=120-3Q2/6

Hence

Q1=120-3(120-3Q1/6)/6

Q1=13.333

In conclusion,

P = 123 - 3(2*13.333)

P=93

Read more about the price

brainly.com/question/19091385

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Answer:

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The interest is due on bonds of $ 100,00 so it is added to the total amount.

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Out of a list of the values 12, 7, 3, 5, 8, and 2, which result would the MIN function return?
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3 0
3 years ago
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Select all the items that describe a free market economy.
Feliz [49]
The items that describe a free market economy are  :
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4 0
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In order to determine net cash provided by operating activities, a company must convert net income from an accrual basis to a ca
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6 0
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The daily demand for parts from a machining workcell JMB to an assembly workcell is 1,600 units. The average processing time is
Karolina [17]

Answer:

Daily demand for parts = 1600 units

Avg processing time = 25 seconds.

Capacity of a container = 250 units

Waiting time of a container before the JMB = 6 hours

Number of containters currently deployed = 10

Solution:

Total number of parts carried by the containter = 10 x 250 = 2500 parts.

Total numbers carried in excess as safety stock = 2500-1600 = 900

Percentage of safety stock = (900/1600) x 100 = 56.25%

If one container is removed total parts carried = 2250 units

Processing time at machine for 250 parts after loading in JMB = 250 x 25 seconds = 1.736 hours, but it has to wait for another 4.26 hours for the next container to be loaded because of the waiting time of the containter is 6 hours.

Processing time at machine for 1600 parts = 1600 x 25 seconds = 11.11 hours

Number of containers required for 1600 parts = 1600/250= 6.4 ~ 7 containters

Waiting time of 7 containers = 7 x 4.26 = 29.82 hours.

If one of the containers has to be removed 1600 parts has to be carried in 6 containers ie., 29.82hours - 6 hours = 23.82hours

Waiting time per container before loading = 23.82/6 = 3.97 hours.

Reduced Total waiting time of the container = 3.97 hours + the processing time of 250 parts = 3.97 + 1.736 =5.7hours ~ 5 hours and 42 minutes

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3 years ago
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