Question

A plane flies 35 km in the direction n 30° w, then flies 60 km in the direction n 60° e. how far is the plane from its original location? 29.64 km 58.21 km 69.46 km 93.66 km

Answer 1

The distance of plane from the starting point is 69.46 km.

Given that the plane first flies 35 km in the direction N30W and then 60 km in the direction N60E.

We have to find the distance of plane from starting point.

We have to use pythagoras theorem in this which says that the square of hypotenuse is equal to sum of squares of the base and perpendicular.

$H^{2} =P^{2} +B^{2}$

From the figure we can say that P=35 km .and B=60 km

In this we have to find the value of H when P=35 and B=60

$H^{2} =35^{2} +60^{2}$

$H^{2}$=1225+3600

$H^{2}$=6946

H=69.46

Hence the distance of plane from starting point is 69.46 km.

Learn more about pythagoras theorem at brainly.com/question/343682

#SPJ4