A plane flies 35 km in the direction n 30° w, then flies 60 km in the direction n 60° e. how far is the plane from its original
1 answer:
The distance of plane from the starting point is 69.46 km.
Given that the plane first flies 35 km in the direction N30W and then 60 km in the direction N60E.
We have to find the distance of plane from starting point.
We have to use pythagoras theorem in this which says that the square of hypotenuse is equal to sum of squares of the base and perpendicular.
From the figure we can say that P=35 km .and B=60 km
In this we have to find the value of H when P=35 and B=60
=1225+3600
=6946
H=69.46
Hence the distance of plane from starting point is 69.46 km.
Learn more about pythagoras theorem at brainly.com/question/343682
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Answer:
On the 12th day, the rumor would have has to all the 1000 employees
Step-by-step explanation:
Given the data in the question;
so, lets consider the rumor spreading thorough the company of 1000 employee;
the given model is; =
+ 1000k
( 1000 -
)
where k is the parameter that depends on how fast the rumor spreads, n is the number of days.
now, lets assume k = 0.0001, lets also assume r₀ = 4
so to find how soon all 1000 employees will have heard the rumor ;
let n be;
then r1 will be;
r1 = r₀ + ( 0.001)r₀(1000-r₀ )
so
r1 = 4 + ( 0.001) × 4× (1000 - 4 )
r1 = 7.984
r2 will be;
r2 = r1 + ( 0.001)r1(1000-r1 )
r2 = 7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )
r2 = 15.904255744
r3 will be;
r3 = r2 + ( 0.001)r2(1000-r2 )
r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )
r3 = 31.555566137
Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.
we will have;
n rₙ
0 4
1 7.984
2 15.904255744
3 31.555566137
4 62.1153785
5 120.372437
6 226.25535
7 401.319217
8 641.58132
9 871.53605
10 983.497013
11 999.727651
12 999.999926
Therefore, On the 12th day, the rumor would have has to all the 1000 employees