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3 years ago

Enter each answer as a whole number. pls help asap

Mathematics

1 answer:

avanturin [10]3 years ago

8 0

Answer:

Step-by-step explanation:

a ) 2

b) 0.2

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How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1

swat32

There are infinitely many solutions.

Algebraically, we can eliminate $z$ and try to solve for $x,y$ :

$x+y+z=1\implies z=1-x-y$

Then

$x^2+y^2+(1-x-y)^2=1$

$\implies x^2+y^2+1-2x+x^2-2y+y^2+2xy=1$

$\implies x^2-x+y^2-y+xy=0$

which is the equation of an ellipse.

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4 years ago

Which of the following rational functions is graphed below?

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Answer:

The rational function that is graphed is B

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3 years ago

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Identify the property or rule 85+0=

frez [133]

IdentityProperty of Addition OR Zero Property

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3 years ago

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Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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3 years ago

For every 1 litre of water used to make a medicine, 193ml of sucrose and 61ml of saline solution are used. Express the amount of

Brilliant_brown [7]

<h3>Answer is the ratio 1000:193:61</h3>

Explanation

1 liter = 1000 mL

For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.

The ratio is therefore 1000:193:61

We cannot simplify this ratio any further because the GCF of those three terms is 1.

A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61

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3 years ago