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mina [271]
2 years ago
13

Evaluate "four dollars less than the cost of a sweater" if a sweater costs $22 a a

Mathematics
1 answer:
AleksAgata [21]2 years ago
7 0
  • The actual cost of the sweater is $18

The question says to evaluate the cost of four dollars less than the cost of a sweater.

To do this, what we have to do is to create a mathematical equation of it.

Less than always insinuates that we are to subtract, and as such, we are going to subtract four dollars from the cost of the sweater to get our final answer.

Four dollars less than the cost of a sweater that costs $22 is

22 - 4 = $18

Learn more about evaluating cost here brainly.com/question/14315509

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10.<br> JKLM is a rhombus KLN is a triangle. Find MKN.
rjkz [21]

Answer:

65°

Step-by-step explanation:

JM = JK (all sides of a rhombus are equal)

Angle JKM = 25° (isosceles triangle)

Angle JKL = 50° (consecutive angles of rhombus)

Angle MKL = 25° (angle subtraction)

Angle MLK = 130° (opposite angles of a rhombus)

Angle KLN = 50° (angles on a straight line)

Angle LKN = 40° (angle sum of triangle)

Angle MKN = 65° (angle addition)

7 0
1 year ago
1. Sonny works as a furinture salesman and earns a base salary of $350 per week plus 6% commission on sales.
muminat

Answer:

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8 0
3 years ago
What is the value of the expression when h = 5? h + 7
taurus [48]

Answer:

12

Step-by-step explanation:

if h=5

then <u>h+7</u> = <u>5+7</u> = <u>12</u>

4 0
2 years ago
Read 2 more answers
Which<br> pair of triangles can be proven congruent by SAS?
Vlada [557]
Triangle B can be proven congruent
8 0
2 years ago
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If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)
SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

1V=1J/C

and the energy units in terms of meters, seconds and kilograms are:

1J= 1kg\frac{m^{2}}{s^{2}}

So the unit of volt is

1V= kg \frac{m^{2}}{Cs^{2}}

So the velocity expression (it can not be read completly) but i guess that it could be as follows

vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}

So the unit analysis would be

vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}

Applying square root

vf_{a} = \frac{m}{s}

7 0
3 years ago
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