Question

In​ 2012, the population of a city was 6.38million. The exponential growth rate was 2.38​% per year.

Answer 1

The exponential growth function is P(t) = 6.38 million x (1.0238^t).

The population of the city in 2018 is 7.35 million.

The year the population would be 9 million is 14.46 years.

The doubling time is 29.12 years.

What is the exponential growth function?

FV = P (1 + r)^n

• FV = Future population
• P = Present population
• R = rate of growth
• N = number of years

6.38 million x (1.0238^t)

Population in 2018 = 6.38 million x (1.0238^6) = 7.35 million

Number of years when population would be 9 million : (In FV / PV) / r

(In 9 / 6.38) / 0.0238 = 14.46 years

Doubling time = In 2 / 0.0238 = 29.12 years

To learn more about exponential functions, please check: brainly.com/question/18760477

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