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dimaraw [331]
3 years ago
12

How do you write a number that has four digits with the same number in all the places

Mathematics
1 answer:
Maksim231197 [3]3 years ago
5 0
Pick any digit except zero. Write it four times on the same line. If you want to, put a comma between the first and the second one. Shazam ! There's your number !
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Rewrite the equation in standard form y= 4/5x+0.85. Enter answer as ax+by=c or ax+by+c=0
Paraphin [41]

At very minimum, move (4/5)x to the other side of the given equation.  Then:

-(4/5)x + y = 0.85.  This is the equation in standard form.

3 0
3 years ago
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
a class has six boys and 14 girls what is the ratio in simplest form that compares number of boys the number of students​
-BARSIC- [3]

Answer:

3:10

Step-by-step explanation:

Boys- 6

Girls- 14

Total students- 20

Boys:Total students

   6   :      20

Simplify:

6/2=3

20/2=10

This is written as:

3:10

➴Hope this helps!

➸CloutAnswers

6 0
3 years ago
3 - 0.8 =<br><br><br>hehehwjjejwjwjwjwjjwhw​
andrey2020 [161]

Answer:

3-0.8= 2.2

Hope that helps!

5 0
3 years ago
Solve the following equation.<br> Round to the nearest tenth.<br> 8 - 5.4x = 9 + 3.3x
Arada [10]

Answer:

x = 0.1

Step-by-step explanation

3 0
3 years ago
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