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vladimir1956 [14]
1 year ago
7

A phone company surveys a sample of current customers to determine if they use their phones most often to text or use the Intern

et. They sort the data by payment plans, as shown below. Plan A: 27 text, 21 Internet Plan B: 13 text, 10 Internet Answer the questions to determine a conditional probability. How many customers are on payment plan B? customers How many of the customers on plan B text? customers What is the probability that a randomly selected customer who is on plan B uses the phone most often to text? Give the answer in fraction form.

Mathematics
1 answer:
DiKsa [7]1 year ago
4 0

Answer:

23 customers on payment plan B

13 customers on plan text B

Probability: 13/23

Step-by-step explanation:

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Pls help i dont know this one
telo118 [61]

Answer:

The answer is A :)

Step-by-step explanation:

6 0
2 years ago
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
50 POINTS!!!!!
Makovka662 [10]

We can adjust the data by adding 4 to everything before we calculate the statistics.  Or we can calculate the statistics on the given data and just add 4 to everything at the end.  We'll get the same answer either way.

Let's sort the seven data points:  5 5 5 7 7 9 10

Those add up to 48 so the mean is 48/7 = 6.9

The one in the middle is 7 so the median = 7

The mode is the most common one, mode = 5

The range is the difference between max and min, so range = 10 - 5 = 5

In the second week we add four to everything.  Since that adds four to the min and max, the range doesn't change.

Answer: mean=10.9, median=11, mode=9, range=5

7 0
3 years ago
Hunter installed tiles on a floor with a length of 12 feet and a width of 9 feet in
salantis [7]
I don’t know if you meant 7 hours or 7 1/2 hours, but if it was in 7 hours, the answer would be around 15 square feet. If it was 7 1/2 hours, it would be 14 square feet.
3 0
3 years ago
Which of the following shows the polynomial below written in descending
liraira [26]

Answer:

C.

Step-by-step explanation:

Looks like C ( if the polynomial in the question contains x6 NOT x).

7 0
3 years ago
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