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Helga [31]
2 years ago
8

An athletic coach conducted an experiment to test whether a four-week stretching and flexibility program reduces the number of m

uscular injuries that occur during athletic events. the coach randomly selected 30 athletes from several sports and randomly assigned 15 athletes to the four-week program. the remaining 15 athletes did not participate in any type of flexibility program during the four weeks. which statements about this study are true?
Mathematics
1 answer:
son4ous [18]2 years ago
3 0

Answer:

The remaining 15 athletes did not participate in any type of flexibility program

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7) Solve the following system of equations below algebraically using substitution.
Pani-rosa [81]

Answer:

x = 3.25

y =4.75

Step-by-step explanation:

In order to Solve the following system of equations below algebraically using substitution method we say that;

let;

8x - 4y = 7 ..................... equation 1

x + y = 8.......................... equation 2

from equation2

x + y = 8.......................... equation 2

x = 8 - y.............................. equation 3

substitute for x in equation 1

8x - 4y = 7 ..................... equation 1

8(8-y) - 4y = 7

64-8y-4y=7

64-12y=7

collect the like terms

64-7 = 12y

57= 12y

divide both sides by the coefficient of y which is 12

57/12 = 12y/12

4.75 = y

y =4.75

put y = 4.75 in equation 3

x = 8 - y.............................. equation 3

x = 8 -4.75

x = 3.25

to check if your answer is correct, put the value of x and y in either equation 1 or 2

from equation 2

x + y = 8.......................... equation 2

3.25 + 4.75 =8

8=8.................... proved

8 0
3 years ago
Y=3x-2<br> Y=2x-5<br> Find X and Y using substitution
tiny-mole [99]

y = 3x -2~~~.....(i)\\\\y = 2x-5~~~.....(ii)\\\\\text{Substitute equation (i) in equation (ii):}\\\\3x-2 = 2x -5\\\\\implies 3x -2x = -5+2\\\\\implies x = -3\\\\\text{Substitute}~ x =-3,~ \text{in equation (i):}\\\\y = 3(-3) -2 = -9 -2 = -11\\\\\text{Hence,}~ (x,y) = (-3,-11)

4 0
2 years ago
Simplify<br> 7^2x^-3y/49x^-3y^-2
olya-2409 [2.1K]
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
4 0
3 years ago
Read 2 more answers
What is a number that when you divide it by 2 and subtract 3.8 from the quotient, you get 7?
Black_prince [1.1K]

Let the number x.

Then the number divided by 2 gives

\frac{x}{2}

Subtract 3.8 from the quotient gives

\frac{x}{2}-3.8

Hence,

\frac{x}{2}-3.8=7\begin{gathered} \frac{x}{2}-3.8=7 \\ \frac{x}{2}=7+3.8=10.8 \\ \Rightarrow x=2\times10.8=21.6 \end{gathered}

x = 21.6

5 0
1 year ago
Need help only good answer plis!
Nesterboy [21]

A. The angles at the intersection of the two lines can be proven to be congruent and complementary . so they meet at a right angle and the lines are perpendicular.

<u>Step-by-step explanation:</u>

In above question, In order to find whether AB ⊥ CD, Using compass construction & rounder , keep the tip at A and cut arcs at line CD . Follow the same process again with tip at B and cut arcs at line CD . Do this both sides of Line CD i.e. on left side of AB & on right side of AB. Now, join the intersection points of both side arcs which are intersecting each other. Now, to prove both are right angle to each other i.e.  AB ⊥ CD , can be done by proving congruent  and complementary , so they meet at a right angle and Hence , the lines are perpendicular i.e. AB is inclined to CD at angle of 90°.

8 0
3 years ago
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