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1 year ago

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Check all the factors of 2. * 0 1 2 3

1 answer:

Dovator [93]1 year ago

5 0

1 and 2 are the only factors of 2

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Does anyone know how to do this help please

statuscvo [17]

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 3^2-3-6\\$

$\rm\implies y = 9 - 3 - 6 \\$

$\rm\implies y = 0$

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

$\rm\implies y = -4$

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

$\rm\implies y = -6$

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 1^2+1-6\\$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

$\rm\implies y = 2$

<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

$\rm\implies y = 6$

<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

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