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Westkost [7]
2 years ago
13

Consider the following functions. f=[(-1,1),(1,-2),(3,-4) and g=[(5,0),(-3,4),(1,1),(-4,1)} Find (f-g)(1) =

Mathematics
1 answer:
Vilka [71]2 years ago
8 0

The difference between the functions give:

(f - g)(1) = f(1) - g(1) = -3

<h3>How to find the difference between the functions?</h3>

For two functions f(x) and g(x), the difference is defined as:

(f - g)(x) = f(x) - g(x).

Then:

(f - g)(1) = f(1) - g(1)

By looking at the given tables, we know that:

f(1) = -2

g(1) = 1

Replacing that we get:

(f - g)(1) = f(1) - g(1) = -2 - 1 = -3

If you want to learn more about difference of functions:

brainly.com/question/17431959

#SPJ1

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Answer:

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Step-by-step explanation:

2(3^2+4^2)=

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4^2/(4x4) = 16

9+16=25        

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2(25)= or 2 x 25= 50

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At the city museum, child admission is $5.70 and adult admission is $9.80 . On Sunday, four times as many adult tickets as child
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5.70c + 9.80a = 1526.60
a = 4c

5.70c + 9.80(4c) = 1526.60
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c = 1526.60/44.90
c = 34 <=== child tickets sold

a = 4c
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3 years ago
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Katyanochek1 [597]

Answer:

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3 years ago
25 POINTS AND BRAINLIEST PLEASE HELP ASAP
dexar [7]
M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=&#10;\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\&#10;\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
5 0
3 years ago
Read 2 more answers
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