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Leviafan [203]
3 years ago
7

8kg ham costs $12/kg. find the cost per pound.

Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

The cost per pound is: $5.45 per pound

Step-by-step explanation:

Given

8kg ham costs $12/kg

To determine

Find the cost per pound

As

1 kg = 2.2 pounds  

Weight of 8kg in ponds = 8 × 2.2 = 17.6 ponds

Cost of ham/pound = $12/2.2 pounds

                                 = $5.45 per pound

Thus, the cost per pound is: $5.45 per pound

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Solve the equation for y. 4x - 5y = 9
babymother [125]

Answer:

y = (4x - 9) / 5 or y = 4/5x - 9/5

Step-by-step explanation:

Solving for y

4x - 5y = 9

-5y = -4x + 9

5y = 4x - 9

y = (4x - 9) / 5 or y = 4/5x - 9/5

3 0
3 years ago
What % of $30,000 = $15,000
sammy [17]
15,000/30,000
0.50
50%

Hope this helps!
5 0
2 years ago
Solve this system of equations:<br> y=2x<br> x=-y+6
LenKa [72]

Answer:

(2,4)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
When solving negative one over five (x − 25) = 7, what is the correct sequence of operations? (5 points) a Multiply each side by
german

Answer:

Hello!!

When solving -\frac{1}{5} (x-25)=7, the correct sequence of operations would be...

Multiply each side by −5, add 25 to each side

Step-by-step explanation:

When completing the order of operations use PEMDAS Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Hope this helps!!

7 0
2 years ago
A rectangular box without a lid is to be made from 48 m2 of cardboard. Find the maximum volume of such a box. SOLUTION We let x,
tatiyna

Answer:

The maximum volume of such box is 32m^3

V = x×y×z = 32 m^3

Step-by-step explanation:

Given;

Total surface area S = 48m^2

Volume of a rectangular box V = length×width×height

V = xyz ......1

Total surface area of a rectangular box without a lid is

S = xy + 2xz + 2yz = 48 .....2

To be able to maximize the volume, we need to reduce the number of variables.

Let assume the rectangular box has a square base,that means; length = width

x = y

Substituting y with x in equation 1 and 2;

V = x^2(z) ....3

x^2 + 4xz = 48 .....4

Making z the subject of formula in equation 4

4xz = 48 - x^2

z = (48 - x^2)/4x .......5

To be able to maximize V, we need to reduce the number of variables to 1, by substituting equation 5 into equation 3

V = x^2 × (48 - x^2)/4x

V = (48x - x^3)/4

differentiating V with respect to x;

V' = (48 - 3x^2)/4

At the maximum point V' = 0

V' = (48 - 3x^2)/4 = 0

Solving for x;

3x^2 = 48

x = √(48/3)

x = √(16)

x = 4

Since x = y

y = 4

From equation 5;

z = (48 - x^2)/4x

z = (48 - 4^2)/4(4)

z = 32/16

z = 2

The maximum volume can be derived by substituting x,y,z into equation 1;

V = xyz = 4×4×2 = 32 m^3

7 0
3 years ago
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