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Leviafan [203]
3 years ago
7

8kg ham costs $12/kg. find the cost per pound.

Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

The cost per pound is: $5.45 per pound

Step-by-step explanation:

Given

8kg ham costs $12/kg

To determine

Find the cost per pound

As

1 kg = 2.2 pounds  

Weight of 8kg in ponds = 8 × 2.2 = 17.6 ponds

Cost of ham/pound = $12/2.2 pounds

                                 = $5.45 per pound

Thus, the cost per pound is: $5.45 per pound

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Which real-world story is represented by the addition problem (–2 1/2) + (–3 1/4) = –5 3/4?
allochka39001 [22]

Answer:

A

Step-by-step explanation:

A is the correct answer because the equation matches option A.

(-2 1/2) + (-3 1/4)

The minus sign in -2 1/2 shows that the submarine descended and then descended again with the addition sign. Though the addition sign can mean that it ascended its incorrect.

With the equation in hand, we can prove that option A is correct.

If the submarine descended 2 1/2 miles then here must be a minus sign next to the 2 1/2. But if it ascended then there would've been an addition sign to show that it ascended. The other value - 3 1/4 also shows that it ascended with the help of the addition sign.

Ascends - values increase from smallest to highest.

Descends - values decrease from highest to smallest.

4 0
3 years ago
Please help is for now
telo118 [61]

Answer:

2

Step-by-step explanation:

Given:

-2(1-4x)=3x+8

Let's distribute the parenthesis

-2+8x=3x+8

Let's subtract -3x from both sides

-2+5x=8

Let's add 2 to both sides

5x=10

Now, let's divide both sides by 5 to get x alone

x=2

Hope this is helpful

7 0
3 years ago
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The figure below is not drawn to scale. ABCD is a parallelogram, Find
Butoxors [25]

\angle BAD=100^{\circ} (opposite angles in a parallelogram)

\angle EAD=80^{\circ} (subtraction)

\angle ADE=65^{\circ} (angles in a triangle add to 180 degrees)

\angle CDA=80^{\circ} (adjacent angles in a parallelogram are supplementary)

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4 0
2 years ago
What is Question I (if m<EBF = 117°, fine m<ABE)​
Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

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∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0
4 years ago
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