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ANTONII [103]
2 years ago
9

Three is less than the sum of a number 8 and 4

Mathematics
1 answer:
zhenek [66]2 years ago
5 0

Answer:

3<x+12

Step-by-step explanation:

You might be interested in
Evaluate the following piecewise function f(1)=
ElenaW [278]

Answer:

I would guess it is 1F

Step-by-step explanation:

There is a 1 infront of the F so 1 times one, I think dont count me on that

6 0
3 years ago
What does x equal???????? please help
Sholpan [36]
<h3>Answer: x = 61</h3>

=============================================

Explanation:

The angle x and the 29 degree angle combine to form a 90 degree angle. This is because the square maker on the left has that angle at 90 degrees, and all of the angles combine to form 180. So 180-90 = 90 is the left over amount.

Add up x and 29 to get 90

x+29 = 90

Solve for x by subtracting 29 from both sides

x+29-29 = 90-29

x+0 = 61

x = 61

--------------

An alternative is to solve the equation below for x

x+29+90 = 180 ... see note below

x+119 = 180

x+119-119 = 180-119 ... subtract 119 from both sides

x = 61

we get the same answer

note: this equation turns into x+29 = 90 if you subtracted 90 from both sides

7 0
3 years ago
What is the greatest common factor of 25, 50, 75,
Komok [63]

Answer:

25

Step-by-step explanation:

5 0
3 years ago
A professor compares the number of students at his school majoring in statistics, engineering, both, or neither.
Ymorist [56]

Answer:

Step-by-step explanation:

3

5 0
3 years ago
A flying squirrel jumped from a tree 11 feet in the air at an initial velocity of 9 feet per sencond. The equation h=-2t^2+9t-11
vovikov84 [41]
This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :)  Anyway...

h=-2t^2+9t+11

A)

dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached

dh/dt=0 only when 4t=9, t=2.25 seconds

h(2.25)=21.125 ft  (21 1/8 ft)

B)

As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.

C)

The squirrel reaches the ground when h=0...

0=-2t^2+9t+11

-2t^2-2t+11t+11=0

-2t(t+1)+11(t+1)=0

(-2t+11)(t+1)=0, since t>0 for this problem...

-2t+11=0

-2t=-11

t=5.5 seconds.

4 0
3 years ago
Read 2 more answers
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