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Nikolay [14]
2 years ago
11

HELP ASAP!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Sauron [17]2 years ago
7 0

Answer:

19

Step-by-step explanation:

ZYW=YWX

2x=180-90-(3x-5)

2x=90-3x+5

2x=95-3x

5x=95

x=19

lisov135 [29]2 years ago
6 0
The answer is 169- 20 but the acute angle of 90 is 5 below
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Zanna’s cousin was born in 1980. If Zanna was born in 1997, how much older, in years, is her cousin?
dalvyx [7]

Answer:

17 years.

Step-by-step explanation:

Zanna was born is 1997

Zanna's cousin was born in 1980

1997 - 1980 = 17

7 0
4 years ago
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This figure is made up of a quadrilateral and a semicircle.
vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

d =\sqrt({ x_{1}-x_{2})^2  +( y_{1} -y_{2}  )^2}

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = \sqrt{(-1-(-2))^2+(2-(-1))^2}

=\sqrt{(-1+2)^2+(2+1)^2}(As negative times negative is positive)

= \sqrt{(1)^2+(3)^2} =\sqrt{1+9}  =\sqrt{10}

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= \sqrt(4-5)^2+(-3-0)^2}

= \sqrt{(-1)^2+(-3)^2}

= \sqrt{1+9} =\sqrt{10}

So the sides AB and CD are equal.

The length of side AD

= \sqrt{(-1-5)^2+(2-0)^2}

= \sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}

The length of side BC

= \sqrt{(-2-4)^2+(-1-(-3))^2}

= \sqrt{(-2-4)^2+(-1+3)^2}

= \sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is \sqrt{40} and width is \sqrt{10}.

Area of a rectangle = length × width

= (\sqrt{40}) (\sqrt{10})

= \sqrt{(40)(10)}=\sqrt{400}

= 20 unit^2

Now the diameter of the semicircle is the side AD = \sqrt{40}

So, the radius of the semi-circle = \frac{\sqrt{40}}{2}

= \frac{\sqrt{(4)(10)}}{2}

= \frac{(\sqrt{4})(\sqrt{10})}{2}

= \frac{2\sqrt{10}}{2} = \sqrt{10}

Area of semi-circle = \frac{1}{2} \pi r^2, where r is the radius.

= \frac{1}{2} \pi  (\sqrt{10})^2

= \frac{1}{2} \pi   (10)

= \frac{(\pi)(10)}{2}

= \frac{10\pi}{2}   = 5\pi = 15.7 unit^2 ( Approximately taken to the nearest tenth)

Total area of the figure = (20+15.7) unit^2 = 35.7 unit^2

We have got the required answer.

Option a is correct here.

3 0
3 years ago
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Hi help me 20 points!
Andrei [34K]

Answer:

I'm pretty sure its D

Step-by-step explanation:

8 0
3 years ago
Challenge Six different names were put into a hat. A name is chosen 117 times and the name Grace
Nadusha1986 [10]

Answer:

20/117; 1/117

Step-by-step explanation:

The total number of outcomes would be different

4 0
3 years ago
Number 1 and number 2 pleasseee​
lina2011 [118]

Answer:

1)

(a) 19 44

(b) 3.96 m

2.01 x 90%= 1.95

1.95 + 2.01

(c)

i] 6

2 events *3 medals per event

ii] 60

simple ratio

iii] 20 including marathon run and high jump events

2)

(a) 8.5 cm

closest round off figure

(b) 4/3πr²

4/3 x π x (8.5)²

303 cm³

4 0
3 years ago
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