X=grams of protein you need daily.
Remember (4%=4/100=0.04).
x=4% of x + 48 g
therefore, we can suggest this equation:
x=0.04x+ 48
x-0.04x=48
0.96x=48
x=48/0.96
x=50
Answer: 50 grams of proteins you need daily.
Other method:
the remaning is equal to =100%-4%=96%
Therefore: 96% of x=48
Remember (96%=96/100=0.96)
we can suggest this equation too.
0.96x=48
x=48/0.96
x=50
Answer:50 grams of proteins you need daily.
Answer:
Step-by-step explanation:
The formula for determining the volume of a cylinder is expressed as
Volume = πr²h
Where
r represents the radius of the cylinder.
h represents the height of the cylinder.
From the information given,
Height = 10 units
Radius = 10 units
Volume = π × 10² × 10
The formula for determining the volume of a cone is expressed as
Volume = 1/3πr²h
Height = 10 units
Base = 10 units
Volume = 1/3 × π × 10² × 10
Since the cone has been carved from the cylinder, the statement that derives the formula to find the volume of container B is
π × 10² × 10 - 1/3 × π × 10² × 10
Answer:
Step-by-step explanation:
The driveway has the shape of a cuboid. The formula for determining the volume if a cuboid is expressed as
Volume = L × W × H
Where
H represents the thickness of the gravel to be added to the driveway.
W represents the width of the driveway.
L represents the length of the driveway.
From the information given,
L = 15 yards
W = 3 yards
H = 6 inches.
36 inches = 1 yard
6 inches = 6/36 = 0.167 yard
Therefore, the volume of gravel required would be
V = 15 × 3 × 0.167 = 7.515 cubic yards
The width of the pathway is 3m
Step-by-step explanation:
Let the width of the pathway be 'w'
The area will be 130 square meters
The dimensions of the garden is 10 x 7
Area = (10+w) (7+w)
130 = 70 + 17w + w^2
w^2 + 17w - 60 = 0
w^2 +20w - 3w - 60 = 0
w ( w + 20) - 3 ( w + 20) = 0
(w + 20) (w - 3) = 0
w = -20 ( or) w = 3
w is the width and cannot be negative.
So, w = 3 meters
The width of the pathway is 3m
Step-by-step explanation:
1) given
2) 2 non - common sides in 1 ray
3) supplemental
5) opposite angles are congruent
