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Helga [31]
2 years ago
11

At the flower store they told her that the vase should be filled for the flowers to last the longest. her cylinder vase has a ra

dius of 3in and a height of 8in. how much water should mary pour into the vase?
Mathematics
1 answer:
Over [174]2 years ago
6 0

Mary should pour around 3.7 liters or 226.08 in³ volume of water in the vase.

Given Information and Formula Used

Radius of the cylindrical vase, r = 3 inches

Height of the cylindrical vase, h = 8 inches

The formula for the volume, V of a cylinder is given as,

V = πr²h

Here, r is the radius of the cylinder and h is the height of the cylinder.

Calculating the Volume

Substituting the given values of r and h in the formula for the volume of cylinder, we get

Volume, V = π(3)²(8)

Using π = 3.14, we have,

V = 3.14(9)(8)

V = 226.08 cubic inches

Volume in Liters

Since, 1 Liter = 61.0237 cubic inches,

1 cubic inch = 1/61.0237 liters

⇒ 226.08 cubic inches = 226.08/61.0237 liters

⇒ 226.08 cubic inches ≈ 3.07 liters

Thus, Mary needs to pour approximately 3.07 liters volume of water in the vase.

Learn more about volume here:

brainly.com/question/1578538

#SPJ4

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The difference between two natural no. is 196 and the ratio of the two no. is 9:5. Find Two
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Answer:

441 and 295

Step-by-step explanation:

Let the natural number be 9x and 5x.

9x-5x=4x=196. x=49

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3 years ago
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The table below shows the radius y, in inches, created by growing algae in x days: Time (x) (days) 1 4 7 10 Radius (y) (inches)
tatuchka [14]
PART A:
Given the table below showing the radius y, in inches, created by growing algae in x days.

Time (x) (days):          1       4        7        10
Radius (y) (inches):    1       8       11       12

We can find the find the correlation coeficient of the data using the table below:
\begin{center}&#10;\begin{tabular}&#10;{|c|c|c|c|c|}&#10;x & y & x^2 & y^2 & xy \\ [1ex]&#10;1 & 1 & 1 & 1 & 1\\&#10;4 & 8 & 16 & 64 & 32\\&#10;7 & 11 & 49 & 121 & 77\\&#10;10 & 12 & 100 & 144 & 120\\ [1ex]&#10;\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230&#10;\end{tabular}&#10;\end{center}

Recall that the correlation coefitient is given by the equation:
r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{ \sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)} }  \\  \\ = \frac{4(230)-(22)(32)}{ \sqrt{(4(166)-(22)^2)(4(330)-(32)^2)} } = \frac{920-704}{ \sqrt{(664-484)(1,320-1,024)}}  \\  \\ = \frac{216}{ \sqrt{180(296)}} = \frac{216}{ \sqrt{53,280} } = \frac{216}{230.8} =0.94

[Notice: even without using the formular to find the value of the correlation coeficient, it can be seen that the value of y strictly increases as the valu of x increases. This means that the value of the correlation coeficient is closer to +1 and from the options the value that is closest to +1 is 0.94]

From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

Recall the for the value of the correlation coeficient closer to +1, the relationship is strong positive, for the value closer to -1, the value is strong negative and for the values closer to zero, either way of zero is a weak positive if it is positive and weak negative if it is negative.


PART B:
Recall that the slope of a straight line passing through two points
(x_1,y_1) and (x_2,y_2)
is given by
m= \frac{y_2-y_1}{x_2-x_1}

Thus the slope of the graph of radius versus time between 4 and 7 days, [i.e. the line passes through points (4, 8) and (7, 11)] is given by
m= \frac{11-8}{7-4}= \frac{3}{3} =1

The value of the slope means that the radius of the algea grows by 1 inch evry day between day 4 and day 7.


PART C:
We can say that the data above represent both correlation and causationg.

Recall that correlation expresses the relationship between two variables while causation expresses that an event is as a result of another event.

From the information above, we have seen that there is a relationship (correlation) between the passing of days and the growth in the radius of the algae.

Also we can conclude that the growth in the radius of algae is a function of the passing of days, i.e. the growth in the radius of algae is as a result of the passing of days.

Therefore, <span>the data in the table represent both correlation and causation.</span>
6 0
3 years ago
How much do you subtract from 87/10 to make 8
kow [346]

Answer:

7/10

Step-by-step explanation:

87/10-x=8

80/10=8,

87/10-8-x=0

7/10=x

so the answer is 7/10

4 0
3 years ago
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The radius of a circle with an area of 8 cm2 will be enlarged by a scale factor of 4.
GarryVolchara [31]

Answer:

I believe the answer is 32 because you multiply it in enlarging.

8 0
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