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serious [3.7K]
2 years ago
10

If ΔABC ≅ΔDEF, then what corresponding parts are congruent?

Mathematics
1 answer:
const2013 [10]2 years ago
6 0

The part of the triangles which are congruent according to the description are; segment AB and segment DE.

<h3>Which parts of the triangles are congruent?</h3>

It follows from the task content that the two triangles ABC and DEF have been established as congruent. On this note, it can be established that by the congruence theorem that corresponding sides which are congruent and whose ratios equal to a constant ratio are segments AB and segment DE.

Read more on congruence theorem;

brainly.com/question/2102943

#SPJ1

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Find the value of each variable. 3x 2y 34
nikklg [1K]

X= 30

Y=28

Step-by-step explanation:

It's a right-angle triangle. So, 3 x 30 will give you a 90 degree angle.

180-90=90

That means the next 2 angles should add to 90.

2x28=56

56+34=90

Hope this helps!

7 0
2 years ago
A cannon ball is launched at 6 feet per second from the top of a platform 12 feet above the ground.
AleksAgata [21]
A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12

b.) The y-intercept is 12

c.) The y-intercept represent the height of the ball at time t = 0

d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
7 0
3 years ago
The area of a triangle that has a base of 7 and a height of 17 is:
Andru [333]

Answer:

59.5

Step-by-step explanation:

First we have to multiply 7 by 17 (7x17).

Then you have to divide it by 2.

1/2 X base x height

8 0
2 years ago
How do you solve this?
Katarina [22]

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] ~\dotfill\\\\ (x-6)^2+(y+5)^2=16\implies [x-\stackrel{h}{6}]^2+[y-(\stackrel{k}{-5})]^2=\stackrel{r}{4^2}~\hfill \begin{cases} \stackrel{center}{(6,-5)}\\ \stackrel{radius}{4} \end{cases}

Check the picture below.

6 0
4 years ago
Read 2 more answers
Jenise throws a ball 75 times and hits the target 41 times. What is the experimental probability that she will hit the target? S
Nutka1998 [239]

Answer:

Step-by-step explanation:

Probability is the ratio of the required outcome to the total possible outcome

Total outcome = 75

Number of times target was hit (expected outcome) = 41

Pr(she will hit target)= 41/75

Next is to state in percent and u do that by multiplying the resulting fraction by 100

41/75 i n percent.

41/75×100

= 4100/75

= 54.67%

Hence the answer in percentage is 54.67%

7 0
3 years ago
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