Answer:
For The value of a = 0 and c = 0 , The given expression equality is true
Step-by-step explanation:
Given expression as :
= a - 2
Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )
Or, 3 a² + ac + 2 c - 6 a = 3 a² - ac - 6 a + 2 c
Or, ( 3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0
Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0
or, 0 + 2 ac + 0
Or, 2 ac = 0
∴ a =0 and c = 0
Hence For The value of a = 0 and c = 0 , The given expression equality is true . Answer
Answer:
50%
Step-by-step explanation:
Hope it helps
Answer:
2:9 4:8
8:3 24:6
9:7 3:2
18:15 6:6
18:12 12:16
10:40 5:9
12:16 6:7
12:36 12:18
45:15 4:5
those in bold are the answer
Answer:
See below
Step-by-step explanation:
a. here you are to multiply the two functions together:

b. here you are to subtract g from f:

c. here you are to compose g into f. In other words, pick up the whole g function and plug it into f wherever you see an x:

d. here you are compose f into g. In other words, pick up the whole f function and plug it into g wherever you see an x:

You now have to FOIL out the (3x-1) like so:
![2[(3x-1)(3x-1)]](https://tex.z-dn.net/?f=2%5B%283x-1%29%283x-1%29%5D)
which gives you

Distribute in the 2 and you'll end up with the answer:
