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Sergeeva-Olga [200]

3 years ago

6

Jill made 20 muffins. She put them into 3 boxes and has two muffins left. How many are in each box if they all contain the same

amount of muffins?

1 answer:

PolarNik [594]3 years ago

6 0

Subtract 2 from 20. Then, divide 18 by 3 and that should give you 6.

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What is negative 3 minus x equals negative 10

OlgaM077 [116]

In order to solve this equation, let's write it out in number form:

-3 - x = -10

In order to isolate 'x' we need to ensure that there is only 'x' on one side. We can get rid of the -3 by adding 3 to both sides:
-3 + 3 - x = -10 +3
-x = -7

Because there are negatives on both sides, you can simply cancel them out:

x = 7

6 0

3 years ago

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Identify the slope of the line<br> y=-4- 1/6x

NemiM [27]

Y=mx+b
y=-1/6x-4
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6 0

2 years ago

How many units long is a segment whose endpoints are (2,3) and (7,15)?

Ahat [919]

Answer:

13 units

Step-by-step explanation:

Distance formula: $d = \sqrt{(x2-x1)^2 + (y2-y1)^2}$

Simply plug in your variables

$d = \sqrt{(7-2)^2 + (15-3)^2}$

$d = \sqrt{5^2 + 12^2}$

$d = \sqrt{25 + 144}$

$d = \sqrt{169}$

d = 13

5 0

3 years ago

Which one will rotate the regular polygon shown onto itself?

sesenic [268]

lets draw a picture of our hexagon:

then, we can rotate 60 degrees counterclockwise (or clockwise) and get the same hexagon. So, the answer is 60 degrees

6 0

1 year ago

In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

7 0

3 years ago