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2 years ago

Pls answer quickly!!!

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

8 0

Answer:

x = 90

y = 100

z = -10

Step-by-step explanation:

To find x and y in the above parallelogram ABCD as shown above, recall that one of the properties of a parallelogram is: the consecutive angles in a parallelogram are supplementary.

This means that the sum of angle A and angle B in the parallelogram ABCD = 180°.

Thus,

(x + 30)° + (x - 30)° = 180°

Solve for x

x + 30 + x - 30 = 180

x + x + 30 - 30 = 180

2x = 180

Divide both sides by 2

2x/2 = 180/2

x = 90

=>Find y:

Also, recall that opposite angles in a parallelogram are congruent.

This means, angle A and angle C in parallelogram ABCD above are equal.

Thus,

(x + 30)° = (y + 20)°

Plug in the value of x to solve for y

90 + 30 = y + 20

120 = y + 20

Subtract 20 from both sides

120 - 20 = y

100 = y

y = 100

=>Find z, if z = x - y

z = 90 - 100

z = -10

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8 0

2 years ago

In 2000, the circulation of a local newspaper was 3,250. In 2001, its circulation was 3,640. In 2002, the circulation was 4,100.

vodka [1.7K]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

Finding percent of increase in the newspaper’s circulation from 2000 to 2001:

$\text { Percent increase from } 2000 \text { to } 2001=\frac{\text { change in circulation from 2001 - 2000 }}{\text { circulation in } 2000} \times 100$

$\begin{array}{l}{=\frac{3640-3250}{3250} \times 100} \\\\ {=\frac{390}{3250} \times 100=12 \%}\end{array}$

Finding percent of increase in the newspaper’s circulation from 2001 to 2002:

$\begin{array}{l}{\text { Percent increase from } 2001 \text { to } 2002=\frac{\text { change in circulation }}{\text {circulation in } 2001} \times 100} \\\\ {=\frac{4100-3640}{3640} \times 100} \\\\ {=\frac{460}{3640} \times 100=12.6 \%}\end{array}$