3x+3x+3x+y+3*2 ?
I only seperated the variabled number
A . Because one you make the ratio 80:48 you simplify (divide until you can divide anymore ).
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
The original answer for that question would be 303.55. The best estimate when you round to the nearest tenth the approximate answer would be 303.6 because the 5 in the hundredths place rounds the 5 in the tenths place to a 6. So the approximate answer would be 303.6....hope this helps.
Answer/Step-by-step explanation:
The missing length can be found by applying pythagorean theorem. Thus:
Missing length = √((8x)² - (2x)²)
Missing length = √(64x² - 4x²)
✔️Missing length = √(60x²) = 2x√15
Plug in the value of x which is 3
Missing length = 2*3√15
✔️Length = 6√5