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seraphim [82]
2 years ago
10

chemical engineer has determined by measurements that there are moles of nickel in a sample of nickel tetracarbonyl. How many mo

les of oxygen are in the sample
Chemistry
1 answer:
zavuch27 [327]2 years ago
6 0

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

According to Stoichiometry

7\ \text{mol C} \times \frac{1\ \text{mol O}}{1\ \text{mol C}}

= 7 mol O

Thus from the above conclusion we can say that A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. 7 moles of oxygen are in the sample.

Learn more about the Stoichiometry here: brainly.com/question/16060223

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: This is the chemical formula for Nickel Tetracarbonyl (a powerfully poisonous liquid used in Nickel Refining).

Ni(CO)₄

A chemical engineer has determined by measurements that there are 7.0 moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in the sample ?

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what is the empirical formula of a compound that contains 15.77% aluminum, 28.11% sulfur and 56.12% oxygen
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<h3>Answer:</h3>

Al₂(SO₄)₃

<h3>Explanation:</h3>

We are given percentage composition of elements in a compound;

  • Aluminium is 15.77%
  • Sulfur is 28.11 %
  • Oxygen is 56.12%

We are required to calculate the empirical formula of the compound.

  • Assuming the mass of the compound is 100 g then the masses of the elements is;

Aluminium = 15.77 g

Sulfur = 28.11

Oxygen = 56.12

We can determine the number of moles of each;

Moles of Aluminium = 15.77 g ÷ 26.98 g/mol

                                 = 0.585 moles

Moles of sulfur = 28.11 g ÷ 32.07 g/mol

                         = 0.877 moles

Moles of Oxygen = 56.12 g ÷ 16.0 g/mol

                            = 3.5075 moles

  • But, the empirical formula is the simplest whole number ratio of elements in a compound.
  • Therefore; we need to get the ratio of moles of the above elements;

Aluminium : Sulfur : Oxygen

0.585 mol  :  0.877 mol : 3.5075 mol

0.585/0.585 : 0.877/0.585 : 3.5075/0.585

    1 : 1.5 : 6

But, we need whole number ratios, therefore;

= (1 : 1.5 : 6 ) × 2

= 2 : 3 : 12

Therefore; the formula of the compound is Al₂S₃O₁₂

The compound is written as Al₂(SO₄)₃

Thus, the empirical formula of the compound is Al₂(SO₄)₃

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