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Anna007 [38]
4 years ago
5

How many moles of water, H2O, contain 2.0×1022 molecules of water? (See the hints for assistance in interpreting scientific nota

tion.)
Express the quantity in moles to two significant figures.
Chemistry
1 answer:
hammer [34]4 years ago
5 0
You have to use Avogadro's number which is 6.02x10^23.  The units of Avogadro's number is molecules/mole so you divide the number of molecules by Avogadro's number which will give you the number of moles.
(2.0x10^22 molecules)/(6.02x10^23 molecules/mole)=0.033 moles
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The reaction betwen aluminum and iron (III) oxide can
Alona [7]

Answer : The mass of Al_2O_3 formed will be, 468.18 grams.

Solution : Given,

Mass of Al = 124 g

Mass of Fe_2O_3 = 601 g

Molar mass of Al = 27 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

Molar mass of Al_2O_3 = 102 g/mole

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{124g}{27g/mole}=4.59moles

\text{ Moles of }Fe_2O_3=\frac{\text{ Mass of }Fe_2O_3}{\text{ Molar mass of }Fe_2O_3}=\frac{601g}{160g/mole}=3.76moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe

From the balanced reaction we conclude that

As, 2 mole of Al react with 1 mole of Fe_2O_3

So, 4.59 moles of O_2 react with \frac{4.59}{2}=2.295 moles of Fe_2O_3

From this we conclude that, Fe_2O_3 is an excess reagent because the given moles are greater than the required moles and Al is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 2 mole of Al react to give 2 mole of Al_2O_3

So, 4.59 moles of O_2 react to give \frac{2}{2}\times 4.59=4.59 moles of Al_2O_3

Now we have to calculate the mass of Al_2O_3

\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3

\text{ Mass of }Al_2O_3=(4.59moles)\times (102g/mole)=468.18g

Therefore, the mass of Al_2O_3 formed will be, 468.18 grams.

3 0
3 years ago
15) Which of the these is a balanced chemical equation?
dangina [55]
The correct answer is C.

On the left:
2 carbon+ 2 oxygen+ 2 oxygen

On the right:
2 carbon+ 4 oxygen (remember to multiply the coefficient and subscript)
5 0
4 years ago
Read 2 more answers
What are the problems with studying the structure of the earth?
elena55 [62]
Well we are not able to see the internal structure of the Earth directly because we can't get at it! The thinnest crust is under the oceans but even that is around 7kms thick, way deeper than we can drill. We have to use indirect methods like earthquakes, and infer the structure from the way the pressure and shear waves produced travel through the Earth. 
7 0
3 years ago
Why wouldn’t a tennis player with two sneakers “bond” to any other tennis players? Why wouldn’t a helium atom with two electrons
aleksklad [387]

Answer:

Explained below.

Explanation:

A tennis player with two sneakers wouldn't bond to any other tennis player because he is already stable and complete with the 2 and doesn't need another players assistance to make him stand well.

However, helium atom with two electrons wouldn't bond to any other atoms because it is stable. This stability arises from the fact that it has two protons and 2 electrons, of which the 2 electrons completely fill its valence shell/outer most shell to make it neutral.

8 0
3 years ago
Ibuprofen, an aspirin substitute, has a mass percent composition of 75.69% C, 8.80% H, and 15.51% O. Calculate its empirical for
Andreas93 [3]

Answer:

C₁₃H₁₈O₂

Explanation:

Empirical formula is the simplest ratio in moles of the elements presents in the compound. Assuming a basis of 100g, we need to convert the mass of each element to moles and, find the ratio of each of these:

<em>Moles C:</em>

75.69g * (1mol / 12.01g) = 6.3 moles of C

<em>Moles H:</em>

8.80g * (1mol / 1.01g) = 8.7 moles of H

<em>Moles O:</em>

15.51g * (1mol / 16g) = 0.97 moles of O

The ratio dividing in the moles of O -Because is the element with the lower amount of moles-:

C = 6.3mol / 0.97mol = 6.5

H = 8.7mol / 0.97mol = 9

O = 0.97mol / 0.97mol = 1

As the ratio must be in whole-numbers, multiplying in 2:

C = 13;

H = 18

O = 2

And empirical formula is:

<h3>C₁₃H₁₈O₂</h3>
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3 years ago
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