Answer:
The celery cells are hypertonic to freshwater but hypotonic to 0.2M solution of NaCl
Explanation:
<em>A hypertonic solution is one that whose concentration is more than that of the sap of the cell placed in it while a hypotonic solution has lesser concentration compared to the cell sap.</em>
When the surrounding solution of a cell has more concentration than the cell sap, water molecules moves from the cell to the surrounding solution until equal concentration is established between the outer and the inner solution. The cell lose water and become flaccid. Such cell is said to be hypotonic to the surrounding solution.
On the other hand, when the surrounding solution has lower concentration than the cell sap, water moves from the surrounding solution into the cell and as a result, such cell becomes turgid. The cell is said to be hypertonic to the surrounding solution.
Water moves from the cell sap to the surrounding 0.2M NaCl solution, meaning that celery cells are hypotonic to 0.2M NaCl. On the other hand, water moves from surrounding freshwater into the cell, meaning that celery cells are hypertonic to freshwater.
Answer:
2.5M
Explanation:
Molarity is the measure of the molar concentration of a solution. It is calculated using the formula below:
Molarity = n/V
Where;
n = number of moles (mol)
V = volume (L)
According to the information about Calcium chloride (CaCl2) provided in this question;
n = 0.5moles
M = 0.20M
Molarity = 0.5/0.2
Molarity = 2.5M
Answer:
No, It would be a unsaturated solution
Explanation:
The solubility of a compound gives us information about how a compound may dissolve or not in a determinate solvent.
In this case we have Z, which in 25 °C the solubility of this compound is 40g/100 mL water. This means that if we have 60 g of Z and try to dissolve it in 100 mL of water, only 40 g of Z will solve and the remaining 20 g will be in the water as precipitate or remaining solid.
Now if you just put 40 g of Z in 100 mL water, it will dissolve completely in water, and in this case, we have a saturated solution. A saturated solution is when you dissolve a determinated quantity of a solute in a determinated quantity of solvent, without remaining of solid or excess of solvent.
According to this explanation, we now have 120 g of Z. To make a saturated solution of Z with this quantity, well, let's do math. If 40 g dissolves in 100 mL, then 80 g would be 200 mL and 120 g would have to be 300 mL of water. But in this case, we have 450 mL of water, we have more than 300 mL, an excess of water, so, the 120 g will dissolve but it's dissolved in more than the needed quantity to be a saturated solution, therefore, we have an unsaturated solution of Z (more solvent than the needed).
Hope this helps.
Answer : The freezing point of a solution is 
Explanation : Given,
Molal-freezing-point-depression constant 
= 
Mass of urea (solute) = 29.82 g
Mass of solvent = 500 g = 0.500 kg
Molar mass of urea = 60.06 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = ?
= freezing point of solvent = 
i = Van't Hoff factor = 1 (for urea non-electrolyte)
= freezing point constant =
m = molality
Now put all the given values in this formula, we get
Therefore, the freezing point of a solution is
The correct answer would more than likely have to be true, i’ve had this question before not to long ago.
