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bija089 [108]
3 years ago
10

In the periodic table how many elements could be classified as metals in group IV?

Chemistry
1 answer:
lord [1]3 years ago
8 0
4 elements are classified in group 4 like titanium, zirconium, hafnium and ruthorfordium
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ivann1987 [24]
The answer is D) The boy uses force to move the rock a distance
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3 years ago
Which aqueous solution has the highest boiling point?a. 0.20 M NaClb. 0.10 M CaCl2c. 0.1 M Ga2(SO4)3d. 0.2 M C6H12O6
abruzzese [7]

Answer:

c. 0.1 M Ga₂(SO₄)₃

Explanation:

The boiling point increasing of a solvent due the addition of a solute follows the formula:

ΔT = K*m*i

<em>Where K is boiling point increasing constant (Depends of the solute), m is molality = molarity when solvent is water, and i is Van't Hoff factor.</em>

<em />

That means the option with the higher m*i will be the solution with the highest boiling point:

a. NaCl has i = 2 (NaCl dissociates in Na⁺ and Cl⁻ ions).

m* i = 0.20*2 = 0.4

b. CaCl₂; i = 3. 3 ions.

m*i= 0.10M * 3 = 0.3

c. Ga₂(SO₄)₃ dissolves in 5 ions. i = 5

m*i = 0.10M*55 = 0.5

d. C₆H₁₂O₆ has i = 1:

m*i = 0.2M*1 = 0.2

The solution with highest boiling point is:

<h3>c. 0.1 M Ga₂(SO₄)₃</h3>
3 0
2 years ago
if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge
Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

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