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2 years ago

6m + 2 - 4m =help with this please

Mathematics

1 answer:

devlian [24]2 years ago

8 0

The answer is: 2(m+1)

First combine like terms.
we do 6m-4m which is 2m
2m+2=?

Second we factor. We notice that both terms have 2.
2(m+1)

by distributive law, the 2 is distributed to m and 1.

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A cereal company fills boxes with 16 ounces of cereal. the acceptable percent error in filling a box is 2.5%. find the least and

miskamm [114]

Least = 16 - 0.025 * 16 = 15.6 ounces
Greatest = 16 + 0.025*16 = 16.4 ounces

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3 years ago

PLEAS HELP ASAP PLEAS 20 points 1 over 3b = 4 over 5. what equals b in this equation?

White raven [17]

Answer:

b = 5/12

Step-by-step explanation:

You have the proportion

1/(3b) = 4/5

Cross multiply to get rid of the fractions...

5 = 12b now solve for b

5/12 = b (divide by 12 on both sides)

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2 years ago

Mr.Joseph recently received a notice that his average gas and electric bill would increase at the beginning of the year. He went

son4ous [18]

Answer:

about 2,546

Step-by-step explanation:

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3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago

The cost C, in dollars, of building m sewing machines at Sienna’s Sewing

bulgar [2K]

So basically function of m (f(m) or in this case C(m)) means the price
so just input the value you put for m for all the other m's in the problem
ex. if you had f(x)=3x and you wanted to find f(4) then you replace and do f(3)=3(4)=12 so f(3)=12 and so on

A. cost of 75 sewing machines
75 is the number you replace m with
C(75)=20(75)^2-830(75)+15,000
simplify
20(5625)-62250+15000
112500-47250
65250
the cost for 75 sewing machines is $65,250

B. we notice that in the equation, that the only negative is -830m
so we want anumber that will be big enough to make -830m destroy as much of the other posities a possible

-830m+20m^2+15000
try to get a number that when multiplied by 830, is almost the same amount as or slightly smaller than 20m2+15000 so we do this
830m<20m^2+15000
subtract 830m from both sides
0<20m^2-830m+15000
factor using the quadratic equation which is
(-b+ the square root of (b^2-4ac))/(2a) or (-b- the square root of (b^2-4ac))/(2a)
in 0=ax^2+bx+c so subsitute 20 for a and -830 for b and 15000 for c
you will get a non-real result I give up on this meathod since it gives some non real numbers so just guess

after guessing and subsituting, I found that the optimal number was 21 sewing machines at a cost of 6420

6 0

3 years ago

Read 2 more answers

6m + 2 - 4m =help with this please ​

6m + 2 - 4m =help with this please