For the first one it is x= (y+3)/4
We use the distance formula for this problem.
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
The distance between point (-2,-2) and point (-2,4).
d = √[(⁻2 - ⁻2)² + (4 - ⁻2)²] = 6 units
Then, compute for 20% of 6 units:
Distance traveled = 6(0.2) = 1.2 units
Use 1.2 units as distance and the starting point (-2,-2). The x-coordinate should still be at -2 because the distance is a straight line as shown in the picture.
1.2 = √[(-2 - ⁻2)² + (y - ⁻2)²]
Solving for y,
y = -0.8
The point is found at (-2,-0.8). This is located at quadrant 3. As to the distance traveled, that would be: 1.2*6 = 6 miles. Thus, the answer is C.
Answer: False
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Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
Answer:
y+(21)=-4(x-7)
Step-by-step explanation:
the point slope equation , two point
m=y2-y1/x2-x1
m=23+21/-4-7=44/-11= -4
y+(21)=-4(x-7)
Answer:
the answer is jk
Step-by-step explanation:
