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lesya692 [45]
3 years ago
11

The system of equations y = - 2x + 3 and y = xis graphed. What is the solution to the system of equations ?

Mathematics
2 answers:
nata0808 [166]3 years ago
5 0

Answer:

(1,1)

Step-by-step explanation:

we have

y=-2x+3 ----> equation A

y=x ----> equation B

we know that

The solution of the system of equations is the intersection point both graphs

The intersection point both graphs is the point (1,1)

see the given graph

therefore

The solution is the point (1,1)

Remember that

if a ordered pair is a solution of a system of equations then the ordered pair must satisfy both equations of the system

<u><em>Verify</em></u>

Substitute the value of x=1 and y=1 in each equation and analyze the result

<em>Equation A</em>

1=-2(1)+3

1=1 ---> is true

so

The ordered pair satisfy the equation A

<em>Equation B</em>

1=1 ---> is true

so

The ordered pair satisfy the equation B

therefore

The ordered pair (1,1) is a solution of the system because satisfy both equations

Vlad1618 [11]3 years ago
4 0

(1,1) is the answer.!

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eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

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3 years ago
How do i find x and y?​
mario62 [17]

Answer:

y=65

x=50

Step-by-step explanation:

exterior angle of a triamgle is equal to sum of two interior angles

so

2y=130(as it is isosceles triangle)

y=65

we know y+y+x=180(sum of all angles of triangle)and (vertically opposite angle)

therefore, x=50

8 0
3 years ago
Read 2 more answers
HELP ASAPP !!!<br> A. x=60;y=140<br><br> B. x=60;y=70<br><br> C. x=105;y=95<br><br> D. x=105;y=47.5
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Answer:

B

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3 years ago
1+2-3+4+5-6+7+8-9...+97+98-99
zaharov [31]

Answer:

  1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

__

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

  1+2-3 = 0

  4+5-6 = 3

  7+8-9 = 6

...

  97+98-99 = 96

So the original series is equivalent to ...

  0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

__

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

  s(n) = n(n+1)/2

__

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

  series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

  1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

  (99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

3 0
2 years ago
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