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Phoenix [80]
2 years ago
7

Which simplified fraction is equal to 0.53 with bar?

Mathematics
1 answer:
Oxana [17]2 years ago
5 0

I assume that 0.53 with a bar means the decimal fraction in which 3 is repeating.

24/45, 8/15, and 48/90 all result in the same decimal value. Thus, we are simply looking for the one that is fully simplified.

The correct answer is 8/15.

Hope this helps!

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If 160 is divided by x, then the remainder is 4. What is the remainder when 315 is divided by x?
frutty [35]
Let us rewrite this equation as:
<em>160/x = some number + 4/x
</em>we can assume that some number of x's can fit into 160, but x is greater than 4 so we have a remainder.
We can figure out by using the remainder that x is completely divisible into (160-4) or 156. Knowing this we can assume that x is some factor of 156 that is greater than 4. 
Let us list the factors of 156
1,2,3,4,6,12,13,26,39,52,78,156
Now let us refer back to the restrictions we put on x.
<em>x must be > 4 as anything less than 4 would divide at least 1 more time into it. So now we are left with a bunch of other factors. And the cool thing is that all of the factors excluding anything that is = or < 4 all work for getting a remainder of 4. Thus we can use the largest factor and set it equal to x.
</em>So x = 156
then if we divide 315 by x or <em>315/x = 315/156 = 2 and a remainder of 3
so the answer would be 3.</em>
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3 years ago
The city of Raleigh has 11100 registered voters. There are two candidates for city council in an upcoming election: Brown and Fe
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http://www.photobucket.com>Click

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Hot dogs are sold in packages of 8, and hot dog buns are sold in packages of 12. What is the smallest number of each that could
Andreyy89
The answer is four. It's like asking to give the least common denominator
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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
4 years ago
Can someone help me with this question
Dmitriy789 [7]

Answer:

The horizontal shift is to the left by 2 units and the vertical shift is down 3 units for this function.

I hope I was able to help!

Step-by-step explanation:

7 0
3 years ago
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