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lys-0071 [83]
3 years ago
10

Ahh sorry! i need help again! question 25! if you can, please include steps! thanks!

Mathematics
2 answers:
astraxan [27]3 years ago
5 0

In this question, we are required to find

2 {x}^{2}  - 3x {y}^{3}

When, x = -2 and y = -1

We just need to plug the values of x and y in the given polynomial to get our required answer.

Given, Polynomial in variable x and y,

2 {x}^{2}  - 3x {y}^{3}

Plugging values of x and y,

2 {( - 2)}^{2}  - 3( - 2)( - 1) {}^{3}

According to PEMDAS, we need to do the exponents first, So let's simplify the exponents,

2(4) - 3( - 2)( - 1)

Opening the parantheses and finding the answer,

2  \times 4 - 3 \times  - 2 \times  - 1

8 -6

\boxed{ \red{2}}

This is our required answer !!

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

expeople1 [14]3 years ago
4 0

Answer:

2

Step-by-step explanation:

2x^2 -3xy^3

Let x=-2 and y =-1

2 ( -2)^2 -3 (-2) (-1)^3

Using PEMDAS, we do exponents first

2 ( 4) - 3(-2) (-1)

Multiply nexy

8 - 6

2

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iragen [17]

This is an ellipse.

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Let's find the center point first. We can do this by finding out the midpoint between the vertices or the foci.

(-9+7)/2=-1

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To find out "b", first see that...

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3 years ago
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Can someone help with this !!!!
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4 0
3 years ago
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