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skad [1K]
2 years ago
15

Caculate the monthly payment for a 5 year car loan of $23,570 at 10.48% interest, compounded monthly

Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
8 0
The answer is d hope this helps
Radda [10]2 years ago
3 0

Answer:

D

Step-by-step explanation:

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.(3x+1)(x-3)<br> Binomial
Dafna11 [192]

Answer:

3x^2−8x−3

Step-by-step explanation:

(3x+1)(x−3)

=(3x+1)(x+−3)

=(3x)(x)+(3x)(−3)+(1)(x)+(1)(−3)

=3x^2−9x+x−3

=3x^2−8x−3

5 0
3 years ago
Solve the inequality <br> 2x-1/x &gt; 1
Grace [21]

Answer:

− 1 /2 < x < 0

or  x > 1

Step-by-step explanation:

Solve the inequality by finding the roots and creating test intervals.

Glad I could help!!

8 0
2 years ago
Read 2 more answers
Can someone please help
Rashid [163]

Answer:

It shifted 6 units down

Step-by-step explanation:

Do the graph normally without the k and compare them side by side.

8 0
2 years ago
Help please I’ll make it brainliest!!!!!
mr Goodwill [35]

Step-by-step explanation:

it is very simple, once you remember that "kilo" means 1000, "mili" means 1/1000, and "centi" means 1/100.

and therefore 1 cg = 10 mg, or 1 cm = 10 mm.

"deci" means 1/10.

and therefore 1 dm = 100 mm, 1dg = 100 mg.

1.

9.32 kg = 9.32×1000 = 9320 g

2.

1.429 g = 1.429/1000 = 0.001429 kg

3.

287 g = 287/1000 = 0.287 kg

4.

4.6 L = 4.6×1000 = 4600 mL

5.

0.119 L = 0.119×1000 = 119 mL

6.

9936 mL = 9936/1000 = 9.936 L

7.

26793 mL = 26793/1000 = 26.793 L

8.

0.06 L = 0.06×1000 = 60 mL

9.

170 cg = 170×10 = 1700 mg

10.

2674 cm = 2674/100 = 26.74 m

11.

9.05 mm = 9.05/100 = 0.0905 dm

12.

2 L = 2×1000 = 2000 mL

13.

62.4 L = 62.4×1000 = 62400 mL

14.

99.9 mm = 99.9/1000 = 0.0999 m

15.

4.34 g = 4.34×100 = 434 cg

16.

10 km = 10×1000 m = 10×1000×1000 = 10000000 mm

17.

65 cL = 65/100 = 0.65 L

18.

105 mL = 105/1000 = 0.105 L

19.

0.27 g = 0.27×100 = 27 cg

20.

7777 m = 7777/1000 = 7.777 km

4 0
1 year ago
Answer quickly and explain and show work
Nezavi [6.7K]

Answer:

Susie is correct the function is x times itself = y.

6 0
3 years ago
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