The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
The second one is a perfect square trinomial
X^2+16x+64
Answer:
<em>angle Y is 29 degrees</em>
<em>angle X is 120 degrees</em>
Step-by-step explanation:
Well, if the triangle is an equilateral, then all the angles are equal to
60 degrees
that means the the angle at the top point is 60+31 = 91 degrees
the right point is 60 degrees
every triangle has 180 degrees total
180 - (91+60) = 29 degrees
NOW FORGET ABOUT THE EQUILATERAL FOR A BIT
180 = 31+x+29
simplify
180 = 60+x
subtract 60 from both sides
120 = x
Answer:
7 hours
Step-by-step explanation:
120 x 7 = 840
Answer:
x = 550 ÷ 33
what are the answer choises
Step-by-step explanation:
