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3 years ago

What is the median for the boys plot?

Mathematics

1 answer:

ollegr [7]3 years ago

7 0

Answer:

Step-by-step explanation:

first you put the numbers in order from least to greatest

1,1,1,1,2,2,2,4,12,13,15,15,15,16,16

next find the middle number(s)

1,1,1,1,2,2,2,<em>4</em>,12,13,15,15,15,16,16

the middle number is your median

*if you have 2 middle numbers just add the then divide it by 2 to find the median

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What value will make the equation below true? Equation: -2.1- ? = -1.50

dezoksy [38]

Answer:

? = −0.6

Step-by-step explanation:

If you preform the opposite operation, you get what ? equals.

-2.1 + 1.50 = -0.6

5 0

2 years ago

-8-n=-3(2n-4) solve for n<br> please help

Masja [62]

-8-n=-6n+12
+8. +8
-n=-6n+20
+6n +6n
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5. 5
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3 years ago

C/5 - 4= -3 pls help!

olya-2409 [2.1K]

Answer:

The value of c from the equation is 5.

Step-by-step explanation:

c/5 - 4 = -3

Add 4 to both sides of the equation.

c/5 = 1

Multiply both sides by 5 to get c by itself.

c = 5

4 0

3 years ago

Read 2 more answers

If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers

seraphim [82]

Answer:

a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

$\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}$

<h2>Simplify it in steps:</h2>

Bring both fractions into common denominator:

$\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}$

Simplify:

$\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =$

$\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =$

$\dfrac{4\sqrt{14} }{7-4} =$

$\dfrac{4}{3} \sqrt{14} }$

Compare the result with given expression to get:

a = 4/3 and b = 0

4 0

2 years ago

Can someone answer this

Lunna [17]

Answer:

$m = \boxed{1} \: \: c = \boxed{4}$

Step-by-step explanation:

$y = x + 4 \\ equating \: it \: with \\ y = mx + c \\ m = \boxed{1} \: \: c = \boxed{4}$

8 0

3 years ago