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1 year ago

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An architect wants an artistic flair to the house he is building, so he designs windows that are three fourths of a circle in sh

ape. The builder is making trim for the windows and needs to know the length of the arc of the outer rim of the window. If the central angle is 270 degrees, and the radius of the partial circle is 30 inches, how much trim is needed for each window? Round your answer to the nearest inch, and enter the number only.

1 answer:

larisa86 [58]1 year ago

7 0

The amount of rim needed for each window is 141.4 in

<h3>How to find the length of the outer rim?</h3>

Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.

<h3>What is an arc?</h3>

An arc is part of section of the circumference of a circle

<h3>What is the length of an arc?</h3>

So, length of arc, L = Ф/360 × 2πR where

Ф = central angle of arc and
R = radius of circle.

Gven that for the window rim

Ф = angle of the rim = 270° and
R = radius of the rim = 30 in

Substituting the values of the variables into the equation for L, we have

L = Ф/360 × 2πR

L = 270°/360° × 2π × 30 in

L = 3/4 × 2π × 30 in

L = 3/2 × π × 30 in

L = 3 × π × 15 in

L = 45π in

L = 141.37 in

L ≅ 141.4 in

So, the amount of rim needed for each window is 141.4 in

Learn more about length of an arc here:

brainly.com/question/8402454

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2 years ago

Rectangle ABCD is similar to rectangle RSTU .

Alenkasestr [34]

Answer:

The scale factor of a dilation from ABCD to RSTU is $\frac{1}{2}$

Step-by-step explanation:

We know that the rectangle ABCD is similar to rectangle RSTU.

Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS

Working with the lengths of the sides :

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Replacing with the values of the lengths (Scale factor : SF) :

$DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}$

$AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}$

Notice that the scale factor is dimensionless.

We can verify this result with the sides AD and BC :

$AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft$

$BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft$

The scale factor (SF) is $\frac{1}{2}$

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2 years ago

Read 2 more answers

If a triangle has sides 4, 6 and 10 and a 2nd similar triangle has a perimeter of 60, find the 2nd largest side of the 2nd trian

algol13

The first triangle has a perimeter of 4+6+10 = 20.

The 2nd longest side is 6/20 = 3/10 of the perimeter. In the larger triangle, the 2nd longest side will have length (3/10)*60 = 18.

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2 years ago

1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.

kkurt [141]

1. The values of p and q are: p=31 and q= 4

2. B(11, 29/5)

Further explanation:

<u>1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.</u>

Given:

M = (15. 1)

(x1, y1) = (p, -2)

(x2, y2) = (-1, q)

The formula for mid-point is:

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M \\Putting\ the\ values\\(\frac{p-1}{2} , \frac{-2+q}{2}) = (15,1)\\Putting\ realtive\ values\ equal\\\frac{p-1}{2} = 15\\p-1 = 15(2)\\p-1 = 30\\p = 30+1\\p = 31\\\frac{-2+q}{2} =1\\-2+q = 2(1) \\-2+q = 2\\q = 2+2 \\q =4$

Hence,

p=31

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<u>2. M is the midpoint of the straight line joining point A (3. 1/5) to point B.If m has coordinates (7. 3), find the coordinates of B.</u>

Here,

(x1,y1) = (3, 1/5)

(x2, y2) = ?

M(x,y) = (7,3)

Putting values in the formula of mid-point

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M\\(\frac{3+x_2}{2} , \frac{1/5+y_2}{2}) = (7,3)\\\frac{3+x_2}{2} = 7\\3+x_2 = 7*2\\3+x_2 = 14\\x_2 = 14-3\\x_2 = 11\\\frac{\frac{1}{5}+y_2}{2} = 3\\{\frac{1}{5}+y_2} = 3*2\\{\frac{1}{5}+y_2} = 6\\y_2 = 6 - \frac{1}{5}\\y_2 = \frac{30-1}{5}\\y_2 = \frac{29}{5}$

So, the coordinates of point B are (11, 29/5) .

Keywords: Finding mid-point, Finding coordinates through mid-point

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