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Tomtit [17]
2 years ago
6

Olivia has made a pyramid model for her history project at school. The pyramid model has a square base. Each triangular side of

the
model has a base length of 10 centimeters and a slant height of 8.9 centimeters. Olivia wants to wrap the pyramid in wrapping paper
before putting it into her school bag.
How much wrapping paper will Olivia need to cover the pyramid?
OA. 178 square centimeters
OB. 89 square centimeters
OC. 456 square centimeters
OD. 278 square centimeters
Mathematics
1 answer:
Tresset [83]2 years ago
3 0

Answer:

278 square centimeters

Step-by-step explanation:

You need to use the Pythagorean Theorm. If you're pyramid is a perfect square, then to the middle the length is 5. Because 10/2 is 5. You then use the Pythagorean Theorm  (a^2 + b^2 =c^2) to find the side length of the traingle. When you square the hypotenuse and subtract the bottom leg sqaured, you are left with 3.46274054 after square rooting it. (c^2-a^2=b^2) Plug these into the equation for a right, rectangluar pyramid. You then get 277.9, rounded, is 278.

Hope this helps!

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Answer:

1. Yes

∆RST ~ ∆WSX

by SAS

2. Yes

∆ABC ~ ∆PQR

by SSS

3. Yes

∆STU ~ ∆JPM

by SAS

4. Yes

∆DJK ~ ∆PZR

by SAS

5. Yes

∆RTU ~ ∆STL

by SAS

5. Yes

∆JKL ~ ∆XYW

by SAS

6. No

7. Yes

∆BEF ~ ∆NML

by SAS

8. Yes

∆GHI ~ ∆QRS

by SSS

9. x=22

10. x=12

Step-by-step explanation:

1. RS/WS=ST/SX and m<RST=m<WSX

2. AB/PQ=8/6=4/3

BC/QR=AC/PR=12/9=4/3

AB/PQ=BC/QR=AC/PR

3. ST/JP=10/15=2/3

SU/JM=14/21=2/3

ST/JP=2/3=SU/JM

and m<TSU=70°=m<PJM

4. DK/PR=8/4=2

JK/ZR=18/9=2

DK/PR=2=JK/ZR

and m<DKJ=65°=m<PRZ

5. RT/ST=UT/LT

and m<RTU=m<STL

6. KL/YW=20/18=10/9

JL/XW=36/24=3/2

KL/YW=10/9≠3/2=JL/XW

7. BF/NL=24/16=3/2

BE/NM=39/26=3/2

BF/NL=3/2=BE/NM

and m<EBF=m<MNL

8. GH/QR=32/20=8/5

HI/RS=40/25=8/5

GI/QS=24/15=8/5

GH/QR=HI/RS=GI/QS=8/5

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Simplifying the fraction on the right side of the equation:

x/33=2/3

Solving for x: Multiplying both sides of the equation by 33:

33(x/33)=33(2/3)

x=11(2)

x=22

10. x/16=9/12

Simplifying the fraction on the right side of the equation:

x/16=3/4

Solving for x: Multiplying both sides of the equation by 16:

16(x/16)=16(3/4)

x=4(3)

x=12

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