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xenn [34]
3 years ago
8

On a coordinate plane, a line with positive slope goes through points (negative 6, negative 4) and (0, 6). A point is at (4, neg

ative 6).
Use the given line and the point not on the line to answer the question.

What is the point on the line perpendicular to the given line, passing through the given point that is also on the y-axis?

(−3.6, 0)
(−2, 0)
(0, −3.6)
(0, −2)
Mathematics
2 answers:
Brums [2.3K]3 years ago
5 0

Answer:

c

Step-by-step explanation:

BartSMP [9]3 years ago
4 0

Answer:

C.) (0, −3.6) on Edgenuity

Step-by-step explanation:

Hope this helps!

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In order to check for regional bias in a widely used standardized test, researchers checked for a difference in the means of ran
lbvjy [14]

Answer:

p-value = 0.369

Step-by-step explanation:

Test of hypothesis which has its the alternative hypothesis as Ha:μ1−μ2≠0 is a two tailed test. Therefore, P-value for a two-tailed test with test statistic t≈−0.90 and the number of degrees of freedom = 208

P-value = 2 X P( t(208) < - 0.90)  

    = 2 X 0.1846

    = 0.369  

6 0
3 years ago
At the start of 2012, the US federal budget had a deficit of more than $1.5×1013. Convert this number to decimal form.
kotegsom [21]

Answer:

Just multiple it

Step-by-step explanation:

1.5 × 1013

1519.5 has your result

7 0
3 years ago
Tina has stacks of 5 cds on each of the 3 shelves. How many cds does she have in all?
ipn [44]
The answer to this is 15 because you would multiply 5*3 to get you answer or you could do 5+5+5 either way it equals 15


3 0
3 years ago
Read 2 more answers
Graph the image of △UVW after a reflection over the line y=-x
aliya0001 [1]

Answer:

9514 1404 393

see attached

Step-by-step explanation:

Reflection over the line x = -1 alters the x-coordinates, but leaves the y-coordinates alone. The image point is as far horizontally from the reflection line as the pre-image point is. Each new x-coordinate is the old one subtracted from twice the x-value of the line of reflection: (x, y) ⇒ (-2-x, y) U(-8, -6) ⇒ U'(6, -6) V(-3, -6) ⇒ V'(1, -6) W(-4, -1) ⇒ W'(2, -1)

4 0
2 years ago
Read 2 more answers
Congress regulates corporate fuel economy and sets an annual gas mileage for cars. A company with a large fleet of cars hopes to
attashe74 [19]

Answer:

a) Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

b) X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c) t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

p_v =P(t_{(49)}>2.81)=0.0035  

d) If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e) The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

\bar X=32.12 represent the sample mean  

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =30.2 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

a. Define the parameter and state the hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 30.2 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 30.2  

Alternative hypothesis:\mu > 30.2  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

b. Define the sampling distribution (mean and standard deviation).

Let X the random variable who represent the variable of interest. And we know that the distribution for X is:

X \sim N(\mu=32.12, \sigma=4.83)

And the distribution for the random sample is given by:

\bar X \sim N(\mu=32.12, \frac{\sigma}{\sqrt{n}}=\frac{4.83}{\sqrt{50}}=0.683)

c. Perform the test and calculate P-value

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{32.12-30.2}{\frac{4.83}{\sqrt{50}}}=2.81    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(49)}>2.81)=0.0035  

d. State your conclusion.

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly higher than 30.2.  

e. Explain what the p-value means in this context.

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct. And for this case is a value to accept or reject the null hypothesis.

6 0
3 years ago
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