Answer:
25p
Step-by-step explanation:
IM NOT SURE IF ITS RIGHT BUT THAT WHAT I THINK. HAVE A NICE DAY!
Answer:
122°
Step-by-step explanation:
The measure of the central angle is twice the measure of the inscribed angle that subtends the same arc.
∠ABC = 2×∠ADC = 2×61°
∠ABC = 122°
Answer:
T + V = 50
2T + (3/2) * V = 90
2T + 1.5V = 90
T = 50 * 1.5 - 90 * 1 / 1 * 1.5 - 2*1 = 30
V = 1 * 90 - 2 * 50 / 1 * 1.5 - 2 * 1 = 20
Step-by-step explanation:
T = 30
V = 20
Answer:
![PQR = 20](https://tex.z-dn.net/?f=PQR%20%3D%2020)
Step-by-step explanation:
Given
Bisector: QS
![PQS = 5x](https://tex.z-dn.net/?f=PQS%20%3D%205x)
![RQS = 2x + 6](https://tex.z-dn.net/?f=RQS%20%3D%202x%20%2B%206)
Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that
![PQS = RQS](https://tex.z-dn.net/?f=PQS%20%3D%20RQS)
Substitute expressions for PQS and RQS
![5x = 2x + 6](https://tex.z-dn.net/?f=5x%20%3D%202x%20%2B%206)
Collect Like Terms
![5x - 2x = 6](https://tex.z-dn.net/?f=5x%20-%202x%20%3D%206)
![3x = 6](https://tex.z-dn.net/?f=3x%20%3D%206)
Divide both sides by 3
![x = 2](https://tex.z-dn.net/?f=x%20%3D%202)
Solving for PQR;
![PQR = PQS + RQS](https://tex.z-dn.net/?f=PQR%20%3D%20PQS%20%2B%20RQS)
![PQR = 5x + 2x + 6](https://tex.z-dn.net/?f=PQR%20%3D%205x%20%2B%202x%20%2B%206)
![PQR = 7x + 6](https://tex.z-dn.net/?f=PQR%20%3D%207x%20%2B%206)
Substitute 2 for x
![PQR = 7 * 2 + 6](https://tex.z-dn.net/?f=PQR%20%3D%207%20%2A%202%20%2B%206)
![PQR = 14 + 6](https://tex.z-dn.net/?f=PQR%20%3D%2014%20%2B%206)
![PQR = 20](https://tex.z-dn.net/?f=PQR%20%3D%2020)