Answer:
i thank it is 25 seconds.
Step-by-step explanation:
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
It is 0.575000. All you have to do is divide the numerator by the denominator.
Answer: x=7.7, y=40
3/x = 15/38.5
38.5*3=115.5
115.5/15= 7.7
x=7.7
3/8 = 15/y
15*8=120
120/3= 40
y=40
orrrr you can just easily find the scale factor which is 5, multiply 8 by 5 and get 40. And 38.5/5 which is 7.7
Answer:
7 without going over
Step-by-step explanation:
