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harina [27]
3 years ago
14

Write the percent as a fraction in simplest form 50%

Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

1/2 means one half.  50% is a half of a whole.   I hope I helped :)

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Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

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3 years ago
Find the domain and range of the function
Karolina [17]
Domain- {-2, 1, 0, 1, 2}
Range- {-2, 0, 2}

My domain is right but I don’t think my range is. I did learn this 4 years ago though so
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What is the vertex of the quadratic function fix=(x-8)(x-2)
VikaD [51]

Answer:

Vertex: (5, -9)

Step-by-step explanation:

fix = (x-8)(x-2)

fix = x^2 - 2x - 8x + 16

fix = x^2 - 10x + 16

a = 1, b = -10, and c = 16

To find vertex:

x = -b/2a

x = -(-10)/2(1)

x = 10/2

x = 5

y = 5^2 - 10(5) + 16

y = 25 -50 + 16

y = -9

Vertex: (5, -9)

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Each (x, y) pair above represents an excellent basketball player’s height, x, and average points per game, y. Enter the data int
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