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Bond [772]
2 years ago
12

HELP PLEASE. Hector built a tent shaped like a rectangular pyramid. The volume of the tent is 56 cubic ft. The area of the base

of the tent is 24 square ft. What is the hieght of Hectors tent in feet?
Mathematics
1 answer:
Elanso [62]2 years ago
4 0

The height of the rectangular pyramid is 7 ft.

<h3>How to get the height of the rectangular pyramid?</h3>

First, we know that the volume of a rectangular pyramid is given by:

V = B*H/3

Where B is the base, H is the height.

First, we know that the volume is 56 ft³, and the base is 24ft², then we can replace these two in the volume equation to get:

56 ft^3 = 24ft^2*H/3

Solving that for H, we get:

H = 3*(56ft^3/24ft^2) = 7ft

The height of the rectangular pyramid is 7 ft.

If you want to learn more about rectangular pyramids:

brainly.com/question/22328884

#SPJ1

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midpoint : it is the point in the middle marking half of the total distance.

therefore,

1)

EV = LE = LV/2

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n + 4 = 12

n = 8

3)

LER and LVO are similar triangles. that means they have the same angles, and the ratio of one corresponding pair of lines or sides between both triangles is the same for all corresponding line pairs.

we know e.g. LE/LV = 1/2.

the same ratio applies then to ER/VO = 1/2 = 18/20p.

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6)

as we have already calculated for 3) :

VO = 36

7)

36 + 20 + 24 = 80

8)

10 + 12 + 18 = 40

9)

remember, the and angles in similar triangles.

LVO = 52°

10)

all angles around a single point in one side of a line are together 180°.

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