Someone help me solve these two problems having trouble solving them

Mathematics

1 answer:

julia-pushkina [17]2 years ago

8 0

The first equation is 5x² - 20x + 27 and the second equation will be y = 3x² + 6x + 15.

<h3>How to compute the equation?</h3>

It should be noted that an equation simply means a formula that's used to express the equality of two expressions that are given in Mathematics.

It should be noted that before solving the equations, it's important to expand the functions that are squared and then solve accordingly. This will be illustrated below.

The first equation that's given is:

y = 5(x - 2)² + 7

= 5(x - 2)(x - 2) + 7

= 5(x² - 2x - 2x + 4) + 7

= 5(x² - 4x + 4) + 7

= 5x² - 20x + 20 + 7

= 5x² - 20x + 27

The second equation given is illustrated as:

y = 3(x + 1)² + 12

y = 3(x + 1)(x + 1) + 12

y = 3(x² + 2x + 1) + 12

y = 3x² + 6x + 3 + 12

y = 3x² + 6x + 15

Learn more about equations on:

brainly.com/question/2972832

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Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. Isolate x in the first equation: 2. Substitute the v

klemol [59]

X + 3y = 7
x = -3y + 7

2x + 4y = 8
2(-3y + 7) + 4y = 8
-6y + 14 + 4y = 8
-2y = 8 - 14
-2y = - 6
y = -6/-2
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x + 3y = 7
x + 3(3) = 7
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x = 7 - 9
x = -2

solution is (-2,3)

6 0

3 years ago

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Alenkasestr [34]

Answer:

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