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3 years ago

What is (-x+3)-(x-5) (needhelp!!!)

Mathematics

1 answer:

Airida [17]3 years ago

8 0

(-x+3)-(x-5)=

-x+3-x+5 =

-2x+8

The answer is -2x+8

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Gre4nikov [31]

Hello ;
(2a)^3 =(2)^3 (a)^3 = 8(a)^3

7 0

4 years ago

Read 2 more answers

Plssss help meeee!!!

pogonyaev

The answer is c b/c you multiply

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3 years ago

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PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

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4 years ago

0.75(3.55a - 6b) simplified please

GREYUIT [131]

Answer:

Step-by-step explanation:

2.66a-6b

3 0

3 years ago

How many times larger

Zigmanuir [339]

2*10^9 i'm pretty sure it would be d.

3 0

3 years ago

What is (-x+3)-(x-5) (needhelp!!!)​

What is (-x+3)-(x-5) (needhelp!!!)