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3 years ago

What is the product of five and a number, decreased by eleven

Mathematics

2 answers:

irakobra [83]3 years ago

5 0

Answer:

5(x)-7

Step-by-step explanation:

hodyreva [135]3 years ago

3 0

Answer:

5x-11

Step-by-step explanation:

This is the word problem as an expression

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(15) ? Is this correct or am I missing something, thanks :)

svetoff [14.1K]

You are correct!

Step 1:Write what you know
Madeline's Height: 6 ftMadeline's Shadow: 108 in
Friend's Height: X (we use X as a variable because his height is unknown)Friend's Shadow: 108 in - 1.5 ft 108 in - 18 in 90 in
Step 2:Set up proportions
6 x----- = -----108 90
Step 3:Cross Multiply & Solve
108x = 540x = 5 ft tall

4 0

3 years ago

Can someone help me

djverab [1.8K]

Step-by-step explanation:

10)

any triangle inscribed into a circle with the baseline being a diameter of the circle must be a right-angled triangle.

the arc angle of 84° means that also the angle at Q is 84°, because the arc angle is the same as the segment angle at the center of the circle (that is how arc sngles are defined).

that means the supplementary angle (together they have 180°) of Q at the inner top angle of the small left triangle is 180 - 84 = 96°.

as the legs of this small left triangle are both the radius of the circle, this triangle is an isoceles triangle (both legs are equally long, and both angles at its baseline are equally large).

remember, the sum of all angles in a triangle is always 180°.

so,

y = (180 - 96)/2 = 42°

x is a complimentary angle (together they are 90°, remember, the large triangle is inscribed and is right-angled) to the second 42° angle

x = 90 - 42 = 48°

11)

y is the supplementary angle to 126°

y = 180 - 126 = 54°

this inner segment angle is the mean value between the 2 outer angles.

54 = (57 + 2nd outer angle of y)/2

108 = 57 + 2nd outer angle of y

2nd outer angle of y = 108 - 57 = 51°

all arc angles around a circle must be 360°.

x = 360 - 57 - 104 - 51 = 148°

12)

again, all arc angles together must be 360°.

y = 360 - 148 = 212°

x is the same angle as the top angle of a triangle inscribed to the right of the chord.

and that angle is half of the opposing arc angle (148°).

it is therefore 148/2 = 74°

and so,

x = 74°

6 0

2 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago

Hi can someone pls pls plsssss help me with this sum

Dafna1 [17]

do 12.5/5 then you will get ur answer

6 0

3 years ago

Which are solutions of the equation x2 – 16 = 0? Check all that apply.

san4es73 [151]

Answer:

x=-4

x=4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers