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2 years ago

Friedrich hayek advocated for the concepts of laissez-faire economic thought and free markets. True or false?.

Business

1 answer:

babymother [125]2 years ago

8 0

It is false that Friedrich hayek advocated for the concepts of laissez-faire economic thought and free.

<h3>What is Hayek theory?</h3>

Hayek theory is on interest rate and how it is an important determinant in economy especially investors.

Savers and investors are very much interested in interest rate as the higher rate the better for them through time. Laissez-faire believes in allowing things to unfold itself without interfering.

Therefore, It is false that Friedrich hayek advocated for the concepts of laissez-faire economic thought and free.

Learn more Hayek theory below

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Chegg - Discuss the differences of productivity measurement in service and manufacturing. Why is productivity improvement more d

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3 years ago

Which living expense needs to be included in the budget of someone renting an apartment?.

scoundrel [369]

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2 years ago

A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se

vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

$\hat p = \frac{X}{n}= \frac{13}{25}= 0.52$

And we want to check if we can use the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

3 0

3 years ago