Answer:
The voltage across resistor is 
Step-by-step explanation:
We are given with Voltage across terminals of a series RL circuit, 
And Resistance R=40Ω
And inductor reactance 
Ω
Since Resistor and inductor are in series, same current flows through both.
And that current, I = 
= 
Therefore voltage across resistor, 
<span><span><span><span>=−<span><span>2x</span>y</span></span>+<span>3x</span></span>+<span>−<span><span>2x</span>y</span></span></span>+<span>3x
</span></span><span>=<span><span>(<span><span>−<span><span>2x</span>y</span></span>+<span>−<span><span>2x</span>y</span></span></span>)</span>+<span>(<span><span>3x</span>+<span>3x)
=-4xy+6x
</span></span></span></span></span>
And the answer is A. =-4xy+6x
Just subsitute the value of x with -2
f(-2) = 2×2(-2) = 2×(-4) = -8
Answer: -8
Answer:
if you draw LMN in the first quadrant, you need to draw L'M'N' in the third quadrant using the same coordinates as LMN but in the negative form.
The line you draw trough L and L' and both other two lines all go through the origin.
C. point because
it is a definition not a term
