<h3>
Answer:</h3>
x² -6x = -13 ⇒ x ∈ {3-2i, 2+2i}
<h3>
Step-by-step explanation:</h3>
To make a=1, divide the equation by the coefficient of x², which is 8.
... x² -6x = -13 . . . . . . your blanks are filled with -6 and -13
Now, to complete the square, add the square of half the x-coefficient:
... (-6/2)² = 9.
... x² -6x +9 = -4 . . . 9 added to both sides
... (x -3)² = -4 . . . . . rewrite as a square
... x -3 = ±2i . . . . . . take the square root
... x = 3 ±2i . . . . . . . add 3
The solutions are the complex numbers x = 3 ±2i.
It would be the square root of 3
Answer:
they unite through the origin at (0,0)
It is the fourth one because proofs always start with the given information
Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
